Python一次更新一个列表元素，直到达到总和（list）

我有一个以全零开头的列表。我想连续向列表中的每个元素添加一个整数，直到整个列表的总和达到某一点

假设我希望列表的总和等于24。当我尝试时，它几乎让我觉得它是有效的：

myList = [0,0,0,0,0,0]

while sum(myList) < 24:
    myList =  [x+1 for x in myList]

---

感谢您的指导。

您需要保留一个索引，在到达终点时循环到前面：

i = 0
while sum(myList) != 22:
    myList[i] += 1
    i = (i + 1) % len(myList)

（i+1）%len（myList）

表达式将索引循环回

0

，否则将增加

i

，使其超出范围

演示：

但是，要知道，在不每次递增一个值的情况下，存在以下情况：

---

您甚至不需要循环，您可以直接构建列表：

target = 22
length = 6

quotient, remainder = divmod(target, length)

out = [quotient+1] * remainder + [quotient] * (length-remainder)

print(out, sum(out))
# [4, 4, 4, 4, 3, 3] 22

i = 0
while sum(myList) != 22:
    myList[i] += 1
    i = (i + 1) % len(myList)

>>> myList = [0, 0, 0, 0, 0, 0]
>>> i = 0
>>> while sum(myList) != 22:
...     myList[i] += 1
...     i = (i + 1) % len(myList)
...
>>> myList
[4, 4, 4, 4, 3, 3]

def distribute(oranges, plates):
    base, extra = divmod(oranges, plates)
    return [base + (i < extra) for i in range(plates)]

>>> distribute(22, 6)
[4, 4, 4, 4, 3, 3]

target = 22
length = 6

quotient, remainder = divmod(target, length)

out = [quotient+1] * remainder + [quotient] * (length-remainder)

print(out, sum(out))
# [4, 4, 4, 4, 3, 3] 22