如何在一个房子里有多个敌人。Python文本RPG

我正在做一个游戏，一个玩家在房子里和怪物战斗。我想弄清楚如何在一个房子里有多个怪物。我不知道如何在列表中创建怪物的实例，或者这是否可行

from random import randint
import subprocess
import platform
import time
import npc, player

class Map:
    def __init__(self, width, height):
        self.width = width
        self.height = height
        self.monsterHouse = []
        self.start = (0, 0)
        self.player = (0, 0)

    def movePlayer(self, d):
        x = self.player[0]
        y = self.player[1]
        pos = None

        if d == "":
          pos = (x, y)
        elif d[0] == 'r':
            pos = (x + 1, y)
        elif d[0] == 'l':
            pos = (x - 1, y)
        elif d[0] == 'u':
            pos = (x, y - 1)
        elif d[0] == 'd':
            pos = (x, y + 1)
        else:
          pos = (x, y)
        

        if pos[0] > -1 and pos[0] < self.width and pos[1] > -1 and pos[1] < self.height:
          if pos not in self.monsterHouse:
            self.player = pos
          elif pos in self.monsterHouse:
            self.player = pos
            clear()
            enterHouse(self)
            # MonsterHouse.modifyPlayer(self.player)
          elif pos in self.start:
            SafeHouse.modifyPlayer(self.player)

def drawGrid(self, width=2):
    for y in range(self.height):
        for x in range(self.width):
            if (x, y) in self.monsterHouse:
                symbol = 'H'
            elif (x, y) == self.player:
                symbol = '$'
            elif (x, y) == self.start:
                symbol = '&'
            else:
                symbol = '.'
            print("%%-%ds" % width % symbol, end="")
        print()


def getHouse(g: Map) -> list:
        out = []
        for i in range(0, 3):
          x = randint(1, g.width-1)
          y = randint(1, g.height-1)
          if x == 0 and y == 0:
            x = 3
            y = 3
          out.append((x,y))
        return out

def enterHouse(self):
    action = input("Monsters House! What do you do? ([a]ttack, [r]un)")
    if action == 'a':
      MonsterHouse.attackPhase(self)
    elif action == 'r':
        self.movePlayer(self, 'l')

def clear():
    subprocess.Popen("cls" if platform.system() == "Windows" else "clear", shell=True)
    time.sleep(.01)

def main():
    g = Map(5, 5)
    g.monsterHouse = getHouse(g)

    while True:
        drawGrid(g)
        d = input("Which way? (r, l, u, d)")
        g.movePlayer(d)
        clear()

class SafeHouse(Map):
  def modifyPlayer(self):
    self.hp = randint(100, 125)

class MonsterHouse(Map):
  def __init__(self, x, y, enemy):
    self.enemy = enemy
    super().__init__(x, y)

  def attackPhase(self):
    houseMonsters = []
    numMonsters = randint(0,10)
    for x in range(numMonsters):
      typeMonster = randint(1, 4)
      #1 = Zombie, 2 = Vampire, 3 = Ghoul, 4 = Werewolf
      if typeMonster == 1:
        houseMonsters += npc.Zombie
      elif typeMonster == 2:
        houseMonsters += npc.Vampire
      elif typeMonster == 3:
        houseMonsters += npc.Ghoul
      elif typeMonster == 4:
        houseMonsters += npc.Werewolf
    
    # print(houseMonsters)

  def modifyPlayer(self, thePlayer):
    if self.enemy.isAlive():
      thePlayer.hp = thePlayer.hp - self.enemy.damage
      print("You have been attacked by the monsters! You have {} HP remaining.".format(thePlayer.hp))
  

if __name__ == '__main__':
    main()

所以我已经设置好了，玩家可以移动到地图上的房子里，他们可以攻击它，也可以逃跑。如果他们攻击它，那么它会在房子里创造随机数量的怪物供玩家攻击

---

我收到的错误是TypeError:“type”对象不可编辑

有几个小错误

首先，要创建对象的新实例，即使没有参数，也需要包含括号

    houseMonsters += npc.Zombie()

第二个问题是，

housenmonsters

是一个列表。说

list+=object

是无效的语法，代码需要使用

list.append（）

，例如：

 houseMonsters.append( npc.Vampire() )

将这些更改包装在一起会产生以下内容的

MonsterHouse.attackPhase（）

：

def attackPhase(self):
    houseMonsters = []
    numMonsters = randint(0,10)
    for x in range(numMonsters):
        typeMonster = randint(1, 4)
        #1 = Zombie, 2 = Vampire, 3 = Ghoul, 4 = Werewolf
        if typeMonster == 1:
            newMonster = npc.Zombie()
        elif typeMonster == 2:
            newMonster = npc.Vampire()
        elif typeMonster == 3:
            newMonster = npc.Ghoul()
        elif typeMonster == 4:
            newMonster = npc.Werewolf()
        # add to the list
        houseMonsters.append( newMonster )

    print( "DEBUG" + str (houseMonsters))

当然，您永远不会看到调试打印，因为代码会在每个循环中清除屏幕。也许在开发过程中，将“清除”更改为只打印一行破折号或类似的内容

& . . . . 
$ H . . H 
. . . . . 
. . . . . 
. . . H . 
Which way? (r, l, u, d)r
----------------------------------
Monsters House! What do you do? ([a]ttack, [r]un)a
DEBUG[<npc.Werewolf object at 0x7f080722acd0>, <npc.Werewolf object at 0x7f0807734810>]

&。
$H。H
. . . . . 
. . . . . 
. . . H
哪条路？（r，l，u，d）r
----------------------------------
怪物之家！你是做什么的？（[a]ttack[r]un）a
调试[，]

我想它就在这里的

攻击阶段

方法中。您的代码创建了一个包含多个对象的列表。有什么问题吗？

& . . . . 
$ H . . H 
. . . . . 
. . . . . 
. . . H . 
Which way? (r, l, u, d)r
----------------------------------
Monsters House! What do you do? ([a]ttack, [r]un)a
DEBUG[<npc.Werewolf object at 0x7f080722acd0>, <npc.Werewolf object at 0x7f0807734810>]