Python 如何从列表中添加/删除项目
我看到很多帖子从列表中加减字符串,但我需要帮助记录这些项目 我想耦合这些项目,所以没有重复只是一个计数器 例: 3个苹果4个桔子2个香蕉 我希望能够一次“拿走”一件物品,因此如果我打电话: “吃苹果” 然后我要检查我的库存,我会: 2个苹果4个桔子2个香蕉 我也想做相反的事情。我想“删除”一个项目,并将其添加到房间的库存中Python 如何从列表中添加/删除项目,python,list,Python,List,我看到很多帖子从列表中加减字符串,但我需要帮助记录这些项目 我想耦合这些项目,所以没有重复只是一个计数器 例: 3个苹果4个桔子2个香蕉 我希望能够一次“拿走”一件物品,因此如果我打电话: “吃苹果” 然后我要检查我的库存,我会: 2个苹果4个桔子2个香蕉 我也想做相反的事情。我想“删除”一个项目,并将其添加到房间的库存中 现在我只知道如何一次摘下所有的苹果,而不是一次只摘一个。此外,我的项目从一个单独的txt文件加载到程序中,每个房间的所有项目都保存在这个文件中。考虑使用字典而不是列表。字典是
现在我只知道如何一次摘下所有的苹果,而不是一次只摘一个。此外,我的项目从一个单独的txt文件加载到程序中,每个房间的所有项目都保存在这个文件中。考虑使用
字典
而不是列表。字典是维护事物的计数的理想工具
:
from random import choice
def get_rooms(file_name):
rooms = {}
with open(file_name) as f:
for l in f:
room = l.split()
room_number = int(room[0])
rooms[room_number] = {}
for index, data in enumerate(room[1:], 1):
if index % 2:
item = data
else:
rooms[room_number][item] = int(data)
return rooms
def generate_tests(number_of_test_actions):
tests = []
for _ in range(number_of_test_actions):
tests.append((choice([1,2,3,4,5,6]),
choice(['Apple', 'Sword', 'Bow', 'Arrow', 'monkey']),
choice(['take', 'drop'])))
return tests
def take_item(room, item):
# generates and propagates KeyError exception if item not in room
room[item] -= 1
if not room[item]:
room.pop(item)
def drop_item(room, item):
if item in room:
room[item] += 1
else:
room[item] = 1
rooms = get_rooms("rooms.txt")
for room, item, action in generate_tests(10):
if action == 'take':
print('taking', item, 'from room', room, ':', rooms[room])
try:
take_item(rooms[room], item)
except KeyError:
print('-- Sorry, no', item, 'in room', room, 'to take')
else:
print('-- took', item, 'from room', room, ':', rooms[room])
elif action == 'drop':
print('dropping', item, 'in room', room, ':', rooms[room])
drop_item(rooms[room], item)
print('-- dropped', item, 'in room', room, ':', rooms[room])
rooms.txt
1 Sword 1 Apple 2
2 Apple 3
3 Bow 1 Arrow 3
4 Arrow 5
5 Bow 1
6 Arrow 10
taking Apple from room 3 : {'Arrow': 3, 'Bow': 1}
-- Sorry, no Apple in room 3 to take
taking Apple from room 4 : {'Arrow': 5}
-- Sorry, no Apple in room 4 to take
dropping monkey in room 6 : {'Arrow': 10}
-- dropped monkey in room 6 : {'monkey': 1, 'Arrow': 10}
dropping Apple in room 5 : {'Bow': 1}
-- dropped Apple in room 5 : {'Apple': 1, 'Bow': 1}
taking Bow from room 3 : {'Arrow': 3, 'Bow': 1}
-- took Bow from room 3 : {'Arrow': 3}
dropping monkey in room 3 : {'Arrow': 3}
-- dropped monkey in room 3 : {'monkey': 1, 'Arrow': 3}
dropping Arrow in room 6 : {'monkey': 1, 'Arrow': 10}
-- dropped Arrow in room 6 : {'monkey': 1, 'Arrow': 11}
taking Bow from room 5 : {'Apple': 1, 'Bow': 1}
-- took Bow from room 5 : {'Apple': 1}
taking Bow from room 4 : {'Arrow': 5}
-- Sorry, no Bow in room 4 to take
taking Bow from room 5 : {'Apple': 1}
-- Sorry, no Bow in room 5 to take
输出
1 Sword 1 Apple 2
2 Apple 3
3 Bow 1 Arrow 3
4 Arrow 5
5 Bow 1
6 Arrow 10
taking Apple from room 3 : {'Arrow': 3, 'Bow': 1}
-- Sorry, no Apple in room 3 to take
taking Apple from room 4 : {'Arrow': 5}
-- Sorry, no Apple in room 4 to take
dropping monkey in room 6 : {'Arrow': 10}
-- dropped monkey in room 6 : {'monkey': 1, 'Arrow': 10}
dropping Apple in room 5 : {'Bow': 1}
-- dropped Apple in room 5 : {'Apple': 1, 'Bow': 1}
taking Bow from room 3 : {'Arrow': 3, 'Bow': 1}
-- took Bow from room 3 : {'Arrow': 3}
dropping monkey in room 3 : {'Arrow': 3}
-- dropped monkey in room 3 : {'monkey': 1, 'Arrow': 3}
dropping Arrow in room 6 : {'monkey': 1, 'Arrow': 10}
-- dropped Arrow in room 6 : {'monkey': 1, 'Arrow': 11}
taking Bow from room 5 : {'Apple': 1, 'Bow': 1}
-- took Bow from room 5 : {'Apple': 1}
taking Bow from room 4 : {'Arrow': 5}
-- Sorry, no Bow in room 4 to take
taking Bow from room 5 : {'Apple': 1}
-- Sorry, no Bow in room 5 to take
查找收藏。计数器
。这是有道理的,唯一的问题是每个房间中的物品必须以以下格式从txt文件导入://1宝剑1苹果2//2苹果3//3弓箭1箭头3//4箭头5//5弓箭1//6箭头10//1我的库存中没有物品。然后,当我进入每个房间时,我可以选择一次取下一件物品。