尝试使用django和python编辑表单

尝试使用django和python编辑表单,python,django,Python,Django,我正试图通过编辑按钮编辑表单 当我在表单中单击“更新”按钮时,出现以下错误: FieldError at /studentapp/editrow/72/ Cannot resolve keyword 'rowid' into field Choices are: address, course, id, name, pub_date, roll 我的回溯显示源自此行的错误 item = get_object_or_404(Studentapp, rowid=id) this line. M

我正试图通过编辑按钮编辑表单

当我在表单中单击“更新”按钮时,出现以下错误:

FieldError at /studentapp/editrow/72/
Cannot resolve keyword 'rowid' into field Choices are: address, course, id, name, pub_date, roll
我的回溯显示源自此行的错误

item = get_object_or_404(Studentapp, rowid=id) this line. 
My models.py的外观如下所示:

class Studentapp(models.Model):
    name = models.CharField(max_length=100)
    roll = models.IntegerField()
    course = models.CharField(max_length=100)
    address = models.CharField(max_length=100)
    pub_date = models.DateTimeField('date published', auto_now=True)

    def __str__(self):
        return '%s %s %s %s' % (self.name, self.roll, self.course, self.address)

    def published_recently(self):
        return self.pub_date >= timezone.now() - datetime.timedelta(days=1)
编辑

我的看法是:

def editrow(request, id):
    item = get_object_or_404(Studentapp, id=id)
    if request.method=="POST":
        form = EntryForm(request.POST, instance=item)
        if form.is_valid():
            post=form.save(commit=False)
            post.save()
            return HttpResponseRedirect(reverse('studentapp:index'), id)
        else:
            form=EntryForm(instance=item)
        return render(request, 'index.html',{'form':form})
    else:
        form=EntryForm(instance=item)
        return render(request, 'index.html',{'form':form})
我的URL.py

url(r'^editrow/(?P<rowid>[0-9]+)/$', views.editrow, name='editrow'),
用于更新条目的表单:

{% load staticfiles %}
  <form action="{% url 'studentapp:editrow' student_detail.id  %}" id="editform" method="POST">
    {% csrf_token%}

      <div class = "form-group">
    <label for = "your_name">
      Your name:
    </label>
    <input class = "form-control" id="new_name" type = "text" name="name" value="{{ student_detail.name }}" placeholder="Enter your name">
  </div>
  <div class="form-group">
    <label for = "course_name">
      Course:
    </label>
    <input id="new_course" class = 'form-control' type = "text" name="course" value="{{ student_detail.course }}" placeholder="Enter your course">
  </div>
  <div class = "form-group">
    <label for = "rollno">
      Roll No.:
    </label>
    <input id="new_rollno" type = "text" class = 'form-control' name="roll" value="{{ student_detail.roll }}" placeholder="Enter your roll number">
  </div>
  <div class = "form-group">
    <label for ="addr">
      Address:
    </label>
    <input id="new_address" type = "text" name="address" class = 'form-control' value="{{ student_detail.address }}" placeholder="Enter your address"/>
  </div>
  <input type = "submit" value="Update" id="update" class = "btn btn-success" style="font-size:18px;" />
</form>

此行不正确,您的模型没有字段rowid

你的网址应该是

url(r'^editrow/(?P<id>[0-9]+)/$', views.editrow, name='editrow'),

# url(r'^editrow/(?P<rowid>[0-9]+)/$', views.editrow, name='editrow'), # WRONG

您可以将整个回溯粘贴到字段中吗?无法解析关键字“rowid”。选项包括:地址、课程、id、名称、发布日期、Roll您的模型没有此字段rowid=id。您的意思是id=id,那么我该怎么办?删除rowid,然后添加id,因为您的模型没有此字段我尝试了此方法。我已删除rowid,但它仍在/studentapp/editrow/72/editrow处显示TypeError,出现意外的关键字参数“rowid”,现在该怎么办?我已用视图更新了我的问题。你能告诉我错误吗?你的URL.py,请添加所有相关内容。您的URL模式对于检测工作内容很重要。我已经添加了我的URL和表单。请检查我的答案,您的URL中也有错误
url(r'^editrow/(?P<id>[0-9]+)/$', views.editrow, name='editrow'),

# url(r'^editrow/(?P<rowid>[0-9]+)/$', views.editrow, name='editrow'), # WRONG