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Python 简单Tweepy Bot转发私有列表时出现TweepError_Python_Twitter_Tweepy - Fatal编程技术网

Python 简单Tweepy Bot转发私有列表时出现TweepError

Python 简单Tweepy Bot转发私有列表时出现TweepError,python,twitter,tweepy,Python,Twitter,Tweepy,因此,我正在制作一个简单的Tweepy机器人,它可以从帐户的私有Twitter列表中转发推文。机器人似乎在Twitter上工作,但它仍然在终端中向我抛出以下错误: File "test.py", line 17, in <module> api.retweet(tweet.id) File "/Users/username/anaconda/lib/python3.6/site-packages/tweepy/binder.py", line 245, in _cal

因此,我正在制作一个简单的Tweepy机器人,它可以从帐户的私有Twitter列表中转发推文。机器人似乎在Twitter上工作,但它仍然在终端中向我抛出以下错误:

  File "test.py", line 17, in <module>
    api.retweet(tweet.id)
  File "/Users/username/anaconda/lib/python3.6/site-packages/tweepy/binder.py", line 245, in _call
    return method.execute()
  File "/Users/username/anaconda/lib/python3.6/site-packages/tweepy/binder.py", line 229, in execute
    raise TweepError(error_msg, resp, api_code=api_error_code)
tweepy.error.TweepError: [{'code': 327, 'message': 'You have already retweeted this tweet.'}]

在我将代码放入函数并调用它之后,现在似乎没有出现错误。知道为什么吗?在我将代码放入函数并调用它之后,我现在似乎没有收到错误。你知道为什么吗?
tweets = api.list_timeline('username', 'username-list')
tweeted = []

while True:
    for tweet in tweets:
        if tweet.id not in tweeted:
            api.retweet(tweet.id)
            tweeted.append(tweet.id)
        elif tweet.id in tweeted:
            pass