有没有从python字典中提取浮点值的方法？

我是Python新手，所以我仍然在为许多简单的事情而挣扎。 我有一本结构如下的词典：

<class 'dict'>
{'1388534400000': {'electricity': 0.0}, '1388538000000': {'electricity': 0.0}, '1388541600000': {'electricity': 0.0},...}

---

假设值中始终有一个键

electronic

，您可以对

electronic

的值进行求和，如下所示

>>> d
{'1388534400000': {'electricity': 0.0}, '1388538000000': {'electricity': 0.0}, '1388541600000': {'electricity': 0.0}}
>>> sum(v['electricity'] for k,v in d.items())
0.0

或者只是

>>> sum(v['electricity'] for v in d.values())
0.0

也许用后者，因为我做了一个基准

>>> import timeit
>>> timeit.timeit("sum(v['electricity'] for k,v in d.items())", setup="d={'1388534400000': {'electricity': 0.0}, '1388538000000': {'electricity': 0.0}, '1388541600000': {'electricity': 0.5}}")
0.4952311920005741
>>> timeit.timeit("sum(v['electricity'] for v in d.values())", setup="d={'1388534400000': {'electricity': 0.0}, '1388538000000': {'electricity': 0.0}, '1388541600000': {'electricity': 0.5}}")
0.4470630470004835

>>> import timeit
>>> timeit.timeit("sum(v['electricity'] for k,v in d.items())", setup="d={'1388534400000': {'electricity': 0.0}, '1388538000000': {'electricity': 0.0}, '1388541600000': {'electricity': 0.5}}")
0.4952311920005741
>>> timeit.timeit("sum(v['electricity'] for v in d.values())", setup="d={'1388534400000': {'electricity': 0.0}, '1388538000000': {'electricity': 0.0}, '1388541600000': {'electricity': 0.5}}")
0.4470630470004835

sum = 0
for key in dict:
    try:
        dict[key] + 2.04
        sum += dict[key]
    except TypeError:
        pass