从文件中每隔第n个（第8个字符）打印一次[Python]

我有一个从文件中转储的长序列位。现在，我想获取这个比特序列，并能够从中提取每8个比特。例如：

100010010101000001001110010001110000110100001010
000110100000101000000000000000000000000000001101
010010010100100001000100010100100000000000000000
etc

将提供：

100110
(extraction from second line)
(extraction from third line)
etc

到目前为止，我有以下代码：

 #/usr/bin/python

 with open("thebits.txt", 'r') as f:
        content = [x.strip('\n') for x in f.readlines()]
        {//logic to extract every 8th bit from each line and print it}

如何从每行中提取每8位？

---

.

您可以使用简单的切片：

with open('thebits.txt', 'r') as f:
    for line in f:
        print line.strip()[7::8]

您的示例文件给出：

100110
000001
100000

---

切片

[7:：8]

从第8行开始每8个字符（从0开始索引7）为您提供一个字符。

假设您希望每一行分别显示：

with open('tmp.txt', 'r') as f:
    for line in f.read().splitlines():
        print(line[7::8])

with open('tmp.txt', 'r') as f:
    for line in f.read().splitlines():
        print(line[7::8])