Python 一次只能使用一个调用函数

我有点不知所措，我修改了一个程序来读取文本文件，但当我试图运行该程序时，它只运行一个调用函数，第三个调用函数出错。当我一次一个地运行他们的工作时，你能帮我找出我做错了什么吗

import sys
def spacejam(diff3):
        '''Used to create spaces between the end of the max length and the students'''
    if len(diff3) == 23:
        space = (" " * 2)
    else:
        space = (" " * (25 - len(diff3)))
return space

def part1(courses):
'''Used to create table 1 of the assignment (printing Department Code,
   Course Number, and Students and finding the total number of students)'''
    total = 0
    for aline in courses: #for loop to check each line of the text file
        values = aline.split() #splits each line into elements
        diff = values[:2] #Sets diff to elements 0-1
        diff = ''.join(diff) #joins elements 0 and 1
        temp = values[-1] #sets temp to the last element
        temp = int(temp)   #makes the last elemet a interger
        total = total + temp #Adds the total of the intergers
        print(diff, values[-1].rjust(4)) #prints the needed values

     print("Total number of students: ", total)  # prints total

def part2(courses):
    '''Used to create table 2 of the assignment (printing Department Code,
    Course Number, Title, and Students)
    limiting the length of the Title to 23 characters'''
    for items in courses:  # For loop for every element in courses
        diff = items.split()  # Splits the elements in courses
        diff2 = diff[2:-1]  # combines elements 2 through -1(not including the last item)
        sep = ' '  # Sets the seperator to space
        diff3 = sep.join(diff2)  # Joins elements 2 through -1 as a string
        diff3 = ('%.23s' % diff3)  # Sets the character limit to 23 and shortens strings over 23 
         #characters
    print(diff[0], diff[1], diff3, spacejam(diff3), diff[-1].rjust(4))  # Prints the results

def part3(courses):
    '''Used to create table 2 of the assignment (printing Department Code,
    Course Number, Title, and Students) sorting the elements in a list and
    lining up the number of students'''
    lines = courses.readlines()
    maxlength = len(max(lines, key=len))

    for items in lines:  # For loop for every element in courses
        diff = items.split()  # Splits the each element in course
        diff2 = diff[:-1]  # Combines elements back together except the last element (-1)
        sep = ' '  # Sets the seperator to space
        diff3 = sep.join(diff2)  # Joins elements except the last element(-1) to a string
        space = (" " * (maxlength - len(diff3)))  # Add spaces between the elements based on the 
       #maxlength
    print(diff3, space, diff[-1].rjust(4))  # Prints results



def main():
    sys.setrecursionlimit(3500000)
    opencourse = open('courses.txt', 'r') #opens and reads a text file

    part1(opencourse)   #calls function part 1
    print('')

    part2(opencourse)  #calls function part 2
    print('')

    part3(opencourse)
    opencourse.close()  #closes opened text file
    main()

下面是我运行此操作时发生的情况：

CS152   21 
CS369    8
CS365  119
CS208   24
CS319   14
MA221   12
MA311    7
MA150   27
CS335   20
IS361   22
MG315    6
Total number of students:  280

回溯（最近一次调用上次）：文件 “C:\Users\lord\OneDrive\Documents\Python\Week 6 assignment 1.py”， 第76行，输入 main（）文件“C:\Users\lord\uOneDrive\Documents\Python\Week 6 assignment 1.py”，第74行，在main中 第三部分（opencourse）文件“C:\Users\lord\OneDrive\Documents\Python\Week 6 assignment 1.py”， 第52行，第3部分 maxlength=len（max（lines，key=len））值错误：max（）arg是一个空序列

---

opencourse

对象是迭代器；每次你读它的时候，它都会在内部跟踪你读过的内容，一旦你读了所有的东西，你就不能再读了。当你在courses中对aline执行

操作时，你在第一个函数中阅读整个迭代器，之后它基本上是“空的”。然后将同一个迭代器传递给其他函数，它们没有什么可做的，因为已经没有什么可读的了

与其将file对象传递给每个函数，我建议先使用
readlines（）
将其转换为字符串列表，然后将该列表传递给每个函数；与迭代器不同，遍历列表不会改变列表。
请将代码重新格式化为有效代码（不要以
''
开头），这非常有意义。对不起，这个愚蠢的问题。@Zelow这不是一个愚蠢的问题。总的来说，我认为这是一个相当好的问题：它包括了一个可复制的例子，预期的与实际的行为，并且可以用一个简洁但不琐碎的答案来回答。