在sklearn python中给出不同答案的管道
我写了两个程序,它们应该遵循相同的逻辑。但他们两人给出了不同的答案 首先-在sklearn python中给出不同答案的管道,python,machine-learning,scikit-learn,artificial-intelligence,logistic-regression,Python,Machine Learning,Scikit Learn,Artificial Intelligence,Logistic Regression,我写了两个程序,它们应该遵循相同的逻辑。但他们两人给出了不同的答案 首先- train_data = train_features[:1710][:] train_label = label_features[:1710][:].ravel() test_data = train_features[1710:][:] test_label = label_features[1710:][:].ravel() def getAccuracy(ans): d = 0 for i i
train_data = train_features[:1710][:]
train_label = label_features[:1710][:].ravel()
test_data = train_features[1710:][:]
test_label = label_features[1710:][:].ravel()
def getAccuracy(ans):
d = 0
for i in range(np.size(ans,0)):
if(ans[i] == test_label[i]):
d+=1
return (d*100)/float(np.size(ans,0))
estimators = [('pps', pps.RobustScaler()), ('clf', LogisticRegression())]
pipe = Pipeline(estimators)
pipe = pipe.fit(train_data,train_label)
ans = pipe.predict(test_data)
getAccuracy(ans)
第二-
train_data = train_features[:1710][:]
train_label = label_features[:1710][:].ravel()
test_data = train_features[1710:][:]
test_label = label_features[1710:][:].ravel()
def getAccuracy(ans):
d = 0
for i in range(np.size(ans,0)):
if(ans[i] == test_label[i]):
d+=1
return (d*100)/float(np.size(ans,0))
def preprocess(features):
return pps.RobustScaler().fit_transform(features)
train_data = preprocess(train_data)
clf = LogisticRegression().fit(train_data,train_label)
test_data = preprocess(test_data)
ans = clf.predict(test_data)
getAccuracy(ans)
第一个给80.81,第二个给84.92。为什么两者都不同?您的第二个代码无效,因为您的“预处理”适合测试集的定标器,这是不应该发生的。另一方面,管道只适合您的列车数据的RobustScaler,然后在测试数据上调用“transform”。感谢您的帮助