如何在Python中获取列表中特定值的范围？

例如，我有一个列表

my_list=[['E', '101_CHEK1'],
['E', '101_CHEK1'],
['E', '101_CHEK1'],
['B', '101_CHEK1'],
['B', '101_CHEK1'],
['E', '101_CHEK1'],
['E', '101_CHEK1'],
['E', '101_CHEK1'],
['B', '101_CHEK1'],
['E', '101_CHEK1']]

如何获取列表中第一个元素的范围，即：[0-2]， B:[3-4]，E:[5-7]。。。。到目前为止，我得出的结论如下：

d={}
a=0
for j,i in enumerate(my_list):
  a+=1
  if i[0] not in d:
    d[i[0]]=[j]
  else:
    d[i[0]].append(j)

{'B'：[3,4,8]，'E'：[0,1,2,5,6,7,9]}

有什么特别的方法我应该遵循吗？最终O/P应为

---

E:[0-2]，B:[3-4]，E:[5-7]

注释中的解释

my_list=[['E', '101_CHEMBL1236539_CHEK1'],['E', '101_CHEMBL1236539_CHEK1'],['E', '101_CHEMBL1236539_CHEK1'],['B', '101_CHEMBL1236539_CHEK1'],['B', '101_CHEMBL1236539_CHEK1'],['E', '101_CHEMBL1236539_CHEK1'],['E', '101_CHEMBL1236539_CHEK1'],['E', '101_CHEMBL1236539_CHEK1'],['B', '101_CHEMBL1236539_CHEK1'],['E', '101_CHEMBL1236539_CHEK1']]

from collections import defaultdict

dic = defaultdict(list)
# create a simple dictionary with element position for each elemets
for i,ele in enumerate(my_list):
    dic[ele[0]] = dic[ele[0]]+[i]

# next problem: get consecutive groups [1,2,4,5,6] ==> (1,2),(4,6)
# You can also use more_iterrools.consecutive_groups here.
# Implementation taken from https://more-itertools.readthedocs.io/en/stable/_modules/more_itertools/more.html#consecutive_groups

from itertools import groupby
from operator import itemgetter

def get_consecutive_groups(iterables):
    groups = []
    for k, g in groupby(enumerate(iterables), key=lambda x: x[0] - x[1]):
        g = list(map(itemgetter(1), g))
        groups.append((g[0],g[-1]))
    return (groups)

#create a new dictionary where we have the groupings stored
new_dic = {}
for key in dic.keys():
    new_dic[key] = get_consecutive_groups(dic[key])
print(new_dic)

输出：

{'E': [(0, 2), (5, 7), (9, 9)], 'B': [(3, 4), (8, 8)]}

{'B': [3, 4, 8], 'E': [0, 1, 2, 5, 6, 7, 9]}

---

嗯，你可以把它缩短：

dict_example = {'B': [x for x in range(len(my_list)) if my_list[x][0] == 'B'], 'E': [x for x in range(len(my_list)) if my_list[x][0] == 'E']}
print(dict_example)

输出：

{'E': [(0, 2), (5, 7), (9, 9)], 'B': [(3, 4), (8, 8)]}

{'B': [3, 4, 8], 'E': [0, 1, 2, 5, 6, 7, 9]}

---

作为字典，您将无法获得预期的结果，因为您有重复键。是否有其他输出或类型？这很好。只是一个问题，我在运行代码时遇到如下错误：

namererror:name'itemgetter'未定义