Python Typeerror:视图必须可调用
当我运行服务器时,会收到一条类型错误消息,告诉我: 我的视图必须是可调用的或列表/元组 从我收集的数据来看,django版本有所不同,为了清晰起见,我使用的是django的最新版本。。。总之,这是我的项目的my views.py和url.py: url.pyPython Typeerror:视图必须可调用,python,django,typeerror,Python,Django,Typeerror,当我运行服务器时,会收到一条类型错误消息,告诉我: 我的视图必须是可调用的或列表/元组 从我收集的数据来看,django版本有所不同,为了清晰起见,我使用的是django的最新版本。。。总之,这是我的项目的my views.py和url.py: url.py from django.conf.urls import url from . import views urlpatterns = [ url(r'^login/$', 'django.contrib.auth.views.l
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^login/$',
'django.contrib.auth.views.login',name='login'),
url(r'^logout/$',
'django.contrib.auth.views.logout',name='logout'),
url(r'^logout-then-login/$',
'django.contrib.auth.views.logout_then_login',name='logout_then_login'),
]
views.py
from django.http import HttpResponse
from django.shortcuts import render
from django.contrib.auth import authenticate, login
from .forms import LoginForm
from django.contrib.auth.decorators import login_required
def user_login(request):
if request.method == 'POST':
form = LoginForm(request.POST)
if form.is_valid():
cd = form.cleaned_data
user = authenticate(username=cd['username'],password=cd['password'])
if user is not None:
if user.is_active:
login(request, user)
return HttpResponse('Authenticated successfully')
else:
return HttpResponse('Disabled account')
else:
return HttpResponse('Invalid login')
else:
form = LoginForm()
return render(request, 'account/login.html', {'form': form})
@login_required
def dashboard(request):
return render(request,
'account/dashboard.html',{'section': 'dashboard'})
尝试将您的url模式更改为以下内容:
urlpatterns = [
url(r'^login/$',
django.contrib.auth.views.login,name='login'),
url(r'^logout/$',
django.contrib.auth.views.logout,name='logout'),
url(r'^logout-then-login/$',
django.contrib.auth.views.logout_then_login,name='logout_then_login'),
]
从版本来看,视图是函数而不是字符串。提供有关错误的详细信息。@gonczor以下是实际错误。…raise TypeError:视图必须可调用,如果是include(),则必须是列表/元组是。在URL模式中,视图必须是对实际视图函数的引用,而不是字符串。您有字符串。@丹尼尔,请您用一个例子解释一下,我迷路了。。谢谢您应该阅读教程,了解您正在使用的Django的正确版本。