python如何编辑文本数据库中的数据?
我有一个小数据库文本文件db.txt:python如何编辑文本数据库中的数据?,python,database,file,text,rewrite,Python,Database,File,Text,Rewrite,我有一个小数据库文本文件db.txt: (peter) name = peter surname = asd year = 23 (tom) name = tom surname = zaq year = 22 hobby = sport (paul) name = paul surname = zxc hobby = music job = teacher 如何从例如tom获取所有数据段?我想加入变量:
(peter)
name = peter
surname = asd
year = 23
(tom)
name = tom
surname = zaq
year = 22
hobby = sport
(paul)
name = paul
surname = zxc
hobby = music
job = teacher
如何从例如tom获取所有数据段?我想加入变量:
(tom)
name = tom
surname = zaq
year = 22
hobby = sport
然后我想更改数据:
replace("year = 22", "year = 23")
并获得:
(tom)
name = tom
surname = zaq
year = 23
hobby = sport
现在添加(职务)和删除(姓氏)数据:
最后将更改的部分重写为旧的db.txt文件:
(peter)
name = peter
surname = asd
year = 23
(tom)
name = tom
year = 23
hobby = sport
job = taxi driver
(paul)
name = paul
surname = zxc
hobby = music
job = teacher
有什么解决方案或提示吗?非常感谢 塞巴斯蒂安评论的附录:使用内存中的SQLite DB。SQLite已经嵌入到Python中,所以只需设置几行即可
此外,除非该格式不能更改,请考虑YAML的文本。Python可以在一个步骤中轻松地转换YAML和Python对象(由Python dict、列表、字符串、实数等组成的对象)
因此,我的建议是使用YAML->Python对象->SQLite DB,然后再返回。按照@aitchnyu的建议使用,并对原始格式进行一些修改,这是一项简单的任务:
import yaml
text = """
peter:
name: peter
surname: asd
year: 23
tom:
name: tom
surname: zaq
year: 22
hobby: sport
paul:
name: paul
surname: zxc
hobby: music
job: teacher
"""
persons = yaml.load(text)
persons["tom"]["year"] = persons["tom"]["year"]*4 # Tom is older now
print yaml.dump(persons, default_flow_style=False)
结果:
paul:
hobby: music
job: teacher
name: paul
surname: zxc
peter:
name: peter
surname: asd
year: 23
tom:
hobby: sport
name: tom
surname: zaq
year: 88
当然,你应该从你的文件中读取“文本”(dB.txt),在完成
之后,你要做很多的查询,比如“添加作业”或“更改年龄”,你应该考虑将你的数据迁移到SQLite数据库,这是一个比非标准文本文件更适合存储和操作数据的解决方案。你的问题更像吗?“我应该使用哪种结构”或者“如果信息发生变化,我真的必须每次读写整个文件吗?”paul:
hobby: music
job: teacher
name: paul
surname: zxc
peter:
name: peter
surname: asd
year: 23
tom:
hobby: sport
name: tom
surname: zaq
year: 88