Python 有没有办法定制numpy.rint功能?
我有一个numpy数组Python 有没有办法定制numpy.rint功能?,python,arrays,numpy,rounding,Python,Arrays,Numpy,Rounding,我有一个numpy数组 a = np.array([[[0.23,0.81],[0.9,0],[1,0.51]], [[0.3,0.75],[0.1,0.2],[1,0.50]]]) 要将其四舍五入为整数,有一个函数numpy.rint a_round = np.rint(a) 该值大于0.5时向上舍入,小于0.5时向下舍入。所以我的输出是: [0.1.][1.0.][1.1.]] [0.1.][0.0.][1.0.]] 问题是,有没有办法定制汇总逻辑?例如,如果要在值大于.3时向上取整,在
a = np.array([[[0.23,0.81],[0.9,0],[1,0.51]], [[0.3,0.75],[0.1,0.2],[1,0.50]]])
要将其四舍五入为整数,有一个函数numpy.rint
a_round = np.rint(a)
该值大于0.5时向上舍入,小于0.5时向下舍入。所以我的输出是:
[0.1.][1.0.][1.1.]]
[0.1.][0.0.][1.0.]]
问题是,有没有办法定制汇总逻辑?例如,如果要在值大于.3时向上取整,在值小于0.3时向下取整,可以使用:
>> a = np.array([[[0.23,0.81],[0.9,0],[1,0.51]], [[0.3,0.75],[0.1,0.2],[1,0.50]]])
array([[[0.23, 0.81],
[0.9 , 0. ],
[1. , 0.51]],
[[0.3 , 0.75],
[0.1 , 0.2 ],
[1. , 0.5 ]]])
>> np.rint(a)
array([[[0., 1.],
[1., 0.],
[1., 1.]],
[[0., 1.],
[0., 0.],
[1., 0.]]])
>> np.where(a<0.3, np.floor(a), np.ceil(a))
array([[[0., 1.],
[1., 0.],
[1., 1.]],
[[1., 1.],
[0., 0.],
[1., 1.]]])
>a=np.array([[0.23,0.81],[0.9,0],[1,0.51],[0.3,0.75],[0.1,0.2],[1,0.50])
数组([[0.23,0.81],
[0.9 , 0. ],
[1. , 0.51]],
[[0.3 , 0.75],
[0.1 , 0.2 ],
[1. , 0.5 ]]])
>>np.rint(a)
数组([[0,1.],
[1., 0.],
[1., 1.]],
[[0., 1.],
[0., 0.],
[1., 0.]]])
>>np.其中(a可用于:
>> a = np.array([[[0.23,0.81],[0.9,0],[1,0.51]], [[0.3,0.75],[0.1,0.2],[1,0.50]]])
array([[[0.23, 0.81],
[0.9 , 0. ],
[1. , 0.51]],
[[0.3 , 0.75],
[0.1 , 0.2 ],
[1. , 0.5 ]]])
>> np.rint(a)
array([[[0., 1.],
[1., 0.],
[1., 1.]],
[[0., 1.],
[0., 0.],
[1., 0.]]])
>> np.where(a<0.3, np.floor(a), np.ceil(a))
array([[[0., 1.],
[1., 0.],
[1., 1.]],
[[1., 1.],
[0., 0.],
[1., 1.]]])
>a=np.array([[0.23,0.81],[0.9,0],[1,0.51],[0.3,0.75],[0.1,0.2],[1,0.50])
数组([[0.23,0.81],
[0.9 , 0. ],
[1. , 0.51]],
[[0.3 , 0.75],
[0.1 , 0.2 ],
[1. , 0.5 ]]])
>>np.rint(a)
数组([[0,1.],
[1., 0.],
[1., 1.]],
[[0., 1.],
[0., 0.],
[1., 0.]]])
>>np.其中(awhere)是通过将布尔值转换为浮点值,对[0,1]范围内的数字执行此操作的另一种简单方法:
>> (a>=0.3).astype(np.float)
array([[[0., 1.],
[1., 0.],
[1., 1.]],
[[1., 1.],
[0., 0.],
[1., 1.]]])
其中,通过将布尔值转换为浮点值,对[0,1]范围内的数字执行此操作的另一种简单方法是:
>> (a>=0.3).astype(np.float)
array([[[0., 1.],
[1., 0.],
[1., 1.]],
[[1., 1.],
[0., 0.],
[1., 1.]]])