Python 嵌套字典到多索引数据帧(3级)

Python 嵌套字典到多索引数据帧(3级),python,dictionary,pandas,Python,Dictionary,Pandas,我想为一个3级嵌套字典做同样的事情 使用三级dict示例 In [1]: import pandas as pd In [2]: dictionary = {'A': {'a': {1: [2,3,4,5,6], ...: 2: [2,3,4,5,6]}, ...: 'b': {1: [2,3,4,5,6], ...: 2: [2,3

我想为一个3级嵌套字典做同样的事情


使用三级dict示例

In [1]: import pandas as pd

In [2]: dictionary = {'A': {'a': {1: [2,3,4,5,6],
   ...:                           2: [2,3,4,5,6]},
   ...:                     'b': {1: [2,3,4,5,6],
   ...:                           2: [2,3,4,5,6]}},
   ...:               'B': {'a': {1: [2,3,4,5,6],
   ...:                           2: [2,3,4,5,6]},
   ...:                     'b': {1: [2,3,4,5,6],
   ...:                           2: [2,3,4,5,6]}}}
下面的词典理解是基于你所链接的问题的理解

In [3]: reform = {(level1_key, level2_key, level3_key): values
   ...:           for level1_key, level2_dict in dictionary.items()
   ...:           for level2_key, level3_dict in level2_dict.items()
   ...:           for level3_key, values      in level3_dict.items()}

In [4]: reform
Out[4]:
{('A', 'a', 1): [2, 3, 4, 5, 6],
 ('A', 'a', 2): [2, 3, 4, 5, 6],
 ('A', 'b', 1): [2, 3, 4, 5, 6],
 ('A', 'b', 2): [2, 3, 4, 5, 6],
 ('B', 'a', 1): [2, 3, 4, 5, 6],
 ('B', 'a', 2): [2, 3, 4, 5, 6],
 ('B', 'b', 1): [2, 3, 4, 5, 6],
 ('B', 'b', 2): [2, 3, 4, 5, 6]}
用于熊猫数据帧

In [5]: pd.DataFrame(reform)
Out[5]:
   A           B
   a     b     a     b
   1  2  1  2  1  2  1  2
0  2  2  2  2  2  2  2  2
1  3  3  3  3  3  3  3  3
2  4  4  4  4  4  4  4  4
3  5  5  5  5  5  5  5  5
4  6  6  6  6  6  6  6  6

In [6]: df = pd.DataFrame(reform).T
Out[6]:
       0  1  2  3  4
A a 1  2  3  4  5  6
    2  2  3  4  5  6
  b 1  2  3  4  5  6
    2  2  3  4  5  6
B a 1  2  3  4  5  6
    2  2  3  4  5  6
  b 1  2  3  4  5  6
    2  2  3  4  5  6
如您所见,您可以通过添加 理解的另一行和元组的新键

额外好处:在索引中添加名称

In [7]: names=['level1', 'level2', 'level3']

In [8]: df.index.set_names(names, inplace=True)

In [9]: df
Out[9]:
                      0  1  2  3  4
level1 level2 level3
A      a      1       2  3  4  5  6
              2       2  3  4  5  6
       b      1       2  3  4  5  6
              2       2  3  4  5  6
B      a      1       2  3  4  5  6
              2       2  3  4  5  6
       b      1       2  3  4  5  6
              2       2  3  4  5  6
检查这个:在StackOverflow上。