Python 从另一个字典值替换字典值

我有两本字典，

第一本和
第二本：

First_Dict = {'Texas': 'Austin', 'California': 'San Diego', 'Florida': 'Miami', 
             'Arizona': 'Phoenix'}

Second_Dict = {'Family1': ['This family went to Arizona.'], 'Family2': ['This 
family went to Texas.'], 'Family3': ['This family went to California.']}

目标：对于
Second\u Dict
中提到的每个状态，我需要将该值与
First\u Dict
上的键匹配。如果存在匹配项，则用
第一个Dict
键中的值替换
第二个Dict
的值

因此，输出将如下所示：

Second_Dict = {'Family1': ['This family went to Phoenix.'], 'Family2': 
          ['This family went to Austin.'], 'Family3': ['This family went to 
            San Diego.']}

我在这件事上被难住了。我们将非常感谢您的指导
 尝试听写理解：

import re
print({k:[' '.join([First_Dict.get(re.sub('[^a-zA-Z]','',i),i) for i in v[0].split()])+'.'] for k,v in Second_Dict.items()})

输出：

{'Family1': ['This family went to Phoenix.'], 'Family2': ['This family went to Austin.'], 'Family3': ['This family went to San Diego.']}

更新：

Second_Dict = {k:[' '.join([First_Dict.get(re.sub('[^a-zA-Z]','',i),i) for i in v[0].split()])+'.'] for k,v in Second_Dict.items()}

然后现在第二条是字典

因此：

是:

@vmx1987也投票赞成这个问题，我回答的每一个问题，我都投票赞成这个问题：-）太好了！我真的需要学习更多关于列表和听写理解的知识。刚开始做python或脚本编写。@vmx1987是的，我认为你有一个好的开始，我可以给你一个链接，指向我从哪里学到的：你将如何编辑代码，而不是仅仅打印结果，它实际上会在字典上永久更改？@vmx1987完成了编辑，刚回到我的电脑，马上就帮你做了：-）
print(Second_Dict)

{'Family1': ['This family went to Phoenix.'], 'Family2': ['This family went to Austin.'], 'Family3': ['This family went to San Diego.']}