Python 如何打印对象的单个值？

我有一个清单，我已经填写了对象。我可以通过以下方式打印整个对象：

print str(vars(theList[0]))

或在循环中：

i = 0
for objects in theList:

     print str(vars(theList[i]))
     i+=1

如果我只想要对象中的一个值，而不是整个对象，该怎么办

编辑试图进一步澄清问题： 假设我有一个十个对象的列表，其中包括姓名、年龄、地址和电话号码。如果我只想要索引1对象的名称，而不是索引1中对象的全部内容，该怎么办。这就是目标

print str(vars(theList[0].itemOne))

上面给出了TypeError:vars参数必须具有uuu dict_uuu_uu属性

我发现另一个问题，建议使用dic而不是VAR，但这不起作用。它只打印了一个很长的列表：

“UUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU"乐","乐","乐","乐","乐","乐","乐","乐","乐","乐,"乐","乐,"乐,"乐,","乐,","乐,"乐,,"乐,,"乐,34etattr_uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu，'rfind'，'rindex'，'rjust'，'rpartition'，'rsplit'，'rstrip'，'splitlines'，'startswith'，'strip'，'swapcase'，'title'，'translate'，'upper'，'zfill']

这是for循环语法。它对列表中的每个项目执行一次for循环体，将项目分配给名称，这里是对象

---

用列表名称替换列表名称，并将对象替换为适当的名称。

要打印列表中第一项的值，只需执行printlistName[0]编辑：我认为实际发生的情况是列表中有列表，因此如果您想要列表中第一项的第一项，则需要执行printlistName[0][0]不，正如我所说，列表是对象列表，而不是列表中的列表，因此printlistName[0][0]不起作用。按照您的建议尝试会引发此错误：对象不支持索引。正如所述，我知道如何从列表中获取值。我想问的是，我如何才能只打印对象中的某些项目，而不打印对象的全部内容。抱歉，没有正确阅读您的帖子。没有重复，我的答案也不起作用。我有ac实际上，我已经查看了该线程并尝试了建议的内容。列表的类型是什么[0]对象？如果类型定义了一个_str__或_repr_uu方法，它可以控制如何将其转换为字符串并显示。否则，您必须自己编写代码来显示其属性，具体取决于它的类型。是的，这很有效！我可以执行printobject.object_u项并获得我想要的结果。

for object in list_name:
    print(object)   # <--- the "body"