如何在python中将CSV变量中的行读取到多维数组中？

字符串如下所示：

x = '''"High";"10";"Assigned";"2012/06/12 10:11:02"
"Low";"20";"Assigned";"2012/06/12 10:11:02"
"Medium";"30";"Assigned";"2012/06/12 10:11:02"'''

x = [
[High, 10, Assigned, 2012/06/12 10:11:02],
[Low, 20, Assigned, 2012/06/12 10:11:02],
[Medium, 30, Assigned, 2012/06/12 10:11:02]]

我希望它是这样的：

x = '''"High";"10";"Assigned";"2012/06/12 10:11:02"
"Low";"20";"Assigned";"2012/06/12 10:11:02"
"Medium";"30";"Assigned";"2012/06/12 10:11:02"'''

x = [
[High, 10, Assigned, 2012/06/12 10:11:02],
[Low, 20, Assigned, 2012/06/12 10:11:02],
[Medium, 30, Assigned, 2012/06/12 10:11:02]]

解析这个的最佳方法是什么

>>> import csv
>>> result = [row for row in csv.reader(x.splitlines(), delimiter=';')]
>>> import pprint
>>> pprint.pprint(result)
[['High', '10', 'Assigned', '2012/06/12 10:11:02'],
 ['Low', '20', 'Assigned', '2012/06/12 10:11:02'],
 ['Medium', '30', 'Assigned', '2012/06/12 10:11:02']]

或者，在一行中：

out = [line.split(';') for line in x.splitlines()]

使用以下各项的单衬套：

给出：

[['High', '10', 'Assigned', '2012/06/12 10:11:02'],
 ['Low', '20', 'Assigned', '2012/06/12 10:11:02'],
 ['Medium', '30', 'Assigned', '2012/06/12 10:11:02']]

---

而且还摆脱了

“

，结果只留下了单引号

”

+1供标准库使用，并且对不同csv方言的可能性非常敏感！