Python Django Taggit：如何打印最常用的标签？

事实上，我正在使用django应用程序。我想知道你是否知道打印最常见标签的方法。我试过了，但没用。。。（给你）。有人能帮帮我吗？

我的解决方案可能有问题，但很有效。尝试：

from collections import defaultdict, Counter
from taggit.models import Tag
from .models import YourModel

tag_frequency = defaultdict(int)


for item in YourModel.objects.all():
    for tag in item.tags.all():
        tag_frequency[tag.name] += 1

Counter(tag_frequency).most_common()

因此，在基于类的视图中，这可能看起来像：

from collections import defaultdict, Counter
from taggit.models import Tag
from .models import YourModel


class YourView(ListView):
    model = YourModel
    context_object_name = "choose_a_name_you_like"
    template_name = "yourmodel/yourmodel_list.html"

    def get_context_data(self):
        context = super(YourView, self).get_context_data() # assigns the original context to a dictionary call context
        tag_frequency = defaultdict(int)

        for item in YourModel.objects.all():
            for tag in item.tags.all():
                tag_frequency[tag.name] += 1

        context['tag_frequency'] = Counter(tag_frequency).most_common() # adds a new item with the key 'tag_frequency' to the context dictionary, which you can then access in your template
        return context

---

我的解决方案可能有点老套，但很有效。尝试：

from collections import defaultdict, Counter
from taggit.models import Tag
from .models import YourModel

tag_frequency = defaultdict(int)


for item in YourModel.objects.all():
    for tag in item.tags.all():
        tag_frequency[tag.name] += 1

Counter(tag_frequency).most_common()

因此，在基于类的视图中，这可能看起来像：

from collections import defaultdict, Counter
from taggit.models import Tag
from .models import YourModel


class YourView(ListView):
    model = YourModel
    context_object_name = "choose_a_name_you_like"
    template_name = "yourmodel/yourmodel_list.html"

    def get_context_data(self):
        context = super(YourView, self).get_context_data() # assigns the original context to a dictionary call context
        tag_frequency = defaultdict(int)

        for item in YourModel.objects.all():
            for tag in item.tags.all():
                tag_frequency[tag.name] += 1

        context['tag_frequency'] = Counter(tag_frequency).most_common() # adds a new item with the key 'tag_frequency' to the context dictionary, which you can then access in your template
        return context

---

Django 1.10、Python 3.5、Django taggit 0.21.3

YourModel.tags.most_common()

和前10个标签：

YourModel.tags.most_common()[:10]

---

Django 1.10、Python 3.5、Django taggit 0.21.3

YourModel.tags.most_common()

和前10个标签：

YourModel.tags.most_common()[:10]

---

非常感谢，但是这段代码是在哪里编写的呢？视图。py？很抱歉离开了一段时间。是的，您可以将这是一个视图，在这种情况下，您将返回您的计数作为一些额外的上下文。我将用一个基于类的示例视图编辑答案。非常感谢，但是这段代码是在哪里编写的呢？视图。py？很抱歉离开了一段时间。是的，您可以将这是一个视图，在这种情况下，您将返回您的计数作为一些额外的上下文。我将使用基于类的示例视图编辑答案。