Python 为什么要忽略多行？

我试图做一个破译游戏，但由于某些原因，它不工作，请帮助

done = 0
guess = 0
import random
a=random.randrange(0,9)
str(a)
b=random.randrange(0,9)
str(b)
c=random.randrange(0,9)
str(c)
d=random.randrange(0,9)
str(d)

print a,b,c,d  #Its on so I can guess the correct number

while done == 0:

   ag=raw_input("Input a single digit between 9 and 0  :  ")
   bg=raw_input("Input a single digit between 9 and 0  :  ")
   cg=raw_input("Input a single digit between 9 and 0  :  ")
   dg=raw_input("Input a single digit between 9 and 0  :  ")
   print ag,bg,cg,dg
   if ag == a and bg == b and cg == c and dg == d:
      print "Well Done! You Got it correct in " ,guess, " times!" 
      done = 1
   else:
      print "Incorrect"
      if ag == a :
         print "You succsessfully guessed the first number!"
      if bg == b :
         print "You succsessfully guessed the second number!"
      if cg == c :
         print "You succsessfully guessed the third number!"
      if dg == d :
         print "You succsessfully guessed the forth number!"

我认为这应该起作用，因为当我得到一些正确的数字时，它会打印出你得到的“n”数字是正确的，但它总是这样显示：

 >> 5 8 3 3
 >> Input a single digit between 9 and 0  :  5
 >> Input a single digit between 9 and 0  :  8
 >> Input a single digit between 9 and 0  :  3
 >> Input a single digit between 9 and 0  :  3
 >> 5 8 3 3
 >> Incorrect

当您执行str（a）时，它不会将a转换为字符串。为此，请执行

a=str（a）

由于a当前是一个整数，当您稍后将

a

与

ag

等进行比较时，检查失败

您需要对当前代码中的

b

、

c

、

d

执行相同的操作

done = 0
guess = 0
import random
a=random.randrange(0,9)
b=random.randrange(0,9)
c=random.randrange(0,9)
d=random.randrange(0,9)
print a,b,c,d  #Its on so I can guess the correct number

while done == 0:

   ag=int(raw_input("Input a single digit between 9 and 0  :  "))
   bg=int(raw_input("Input a single digit between 9 and 0  :  "))
   cg=int(raw_input("Input a single digit between 9 and 0  :  "))
   dg=int(raw_input("Input a single digit between 9 and 0  :  "))
   print ag,bg,cg,dg
   if ag == a and bg == b and cg == c and dg == d:
      print "Well Done! You Got it correct in " ,guess, " times!" 
      done = 1
   else:
      print "Incorrect"
      if ag == a :
         print "You succsessfully guessed the first number!"
      if bg == b :
         print "You succsessfully guessed the second number!"
      if cg == c :
         print "You succsessfully guessed the third number!"
      if dg == d :
         print "You succsessfully guessed the forth number!"

---

现在，我认为您找到了解决此问题的正确方法。

您很可能需要将

字符串

值从STDIN转换为

整数

值-。此外，考虑制作<代码>完成< <代码> >代码BooLoe< /Cord>。@ Trand and MistelyError：如果您的查询已被解决，请不要忘记：“ObjISSpIDER，因为OP使用STR（A），所以我认为这是更好的方式来指出…当然，另一种方法也适用。