如何在python中将输出更改为单个列表？

o/p-['8']['6']['4']['6']['8']['8']['2']

我正在尝试从列表中删除所有奇数，我已将所有数字转换为字符串，但打印后会得到多个列表

def purify(num):
    for number in num:
        if number%2 == 0:
            number = list(str(number))
            print(number)


purify([1,8,9,6,5,3,4,6,5,8,8,9,9,2,3,1,5])

试试这个。您需要一个列表来存储这些号码。输出：

def purify(num):
    newlist=[]
    for number in num:
        if number%2 == 0:
            number = str(number)
            newlist.append(number)
    print(newlist)
    return newlist

num = [1,8,9,6,5,3,4,6,5,8,8,9,9,2,3,1,5]
newlist = [str(i) for i in num if i%2==0]
print(newlist)

试试这个。您需要一个列表来存储这些号码。输出：

def purify(num):
    newlist=[]
    for number in num:
        if number%2 == 0:
            number = str(number)
            newlist.append(number)
    print(newlist)
    return newlist

num = [1,8,9,6,5,3,4,6,5,8,8,9,9,2,3,1,5]
newlist = [str(i) for i in num if i%2==0]
print(newlist)

---

以下是同样的方法：

['8', '6', '4', '6', '8', '8', '2']

它给出的o/p如下所示：

---

以下是同样的方法：

['8', '6', '4', '6', '8', '8', '2']

它给出的o/p如下所示：

然后

然后

---

如果您最后的结果是奇数，则可以尝试：

>>> purify([1,8,9,6,5,3,4,6,5,8,8,9,9,2,3,1,5])
['8']['6']['4']['6']['8']['8']['2']

输出：

ls=[1,8,9,6,5,3,4,6,5,8,8,9,9,2,3,1,5]
print(list(filter(lambda x:not x%2,ls)))

如果要在字符串中输入：

[8, 6, 4, 6, 8, 8, 2]

---

如果您最后的结果是奇数，则可以尝试：

>>> purify([1,8,9,6,5,3,4,6,5,8,8,9,9,2,3,1,5])
['8']['6']['4']['6']['8']['8']['2']

输出：

ls=[1,8,9,6,5,3,4,6,5,8,8,9,9,2,3,1,5]
print(list(filter(lambda x:not x%2,ls)))

如果要在字符串中输入：

[8, 6, 4, 6, 8, 8, 2]