Python 从XML中删除父元素和所有子元素
给定具有以下结构的XML文件:Python 从XML中删除父元素和所有子元素,python,xml,python-2.7,elementtree,Python,Xml,Python 2.7,Elementtree,给定具有以下结构的XML文件: <Root> <Stuff></Stuff> <MoreStuff></MoreStuff> <Targets> <Target> <ID>12345</ID> <Type>Ground</Type> <Size>
<Root>
<Stuff></Stuff>
<MoreStuff></MoreStuff>
<Targets>
<Target>
<ID>12345</ID>
<Type>Ground</Type>
<Size>Large</Size>
</Target>
<Target>
...
</Target>
</Targets>
</Root>
这种方法的问题是只删除了
子元素,但是我需要删除整个
元素及其所有子元素。有人能帮忙吗!谢谢。不幸的是,元素树元素不知道他们的父母是谁。有一个解决办法--
未测试您需要保留对Targets元素的引用,以便可以删除其子元素,因此从那里开始迭代。抓住每一个目标,检查你的状况,移除你不喜欢的东西
#!/usr/bin/env python
import xml.etree.ElementTree as ET
xmlstr="""<Root>
<Stuff></Stuff>
<MoreStuff></MoreStuff>
<Targets>
<Target>
<ID>12345</ID>
<Type>Ground</Type>
<Size>Large</Size>
</Target>
<Target>
...
</Target>
</Targets>
</Root>"""
root = ET.fromstring(xmlstr)
targets = root.find('Targets')
for target in targets.findall('Target'):
_id = target.find('ID')
if _id is not None and '12345' in _id.text:
targets.remove(target)
print ET.tostring(root)
#/usr/bin/env python
将xml.etree.ElementTree作为ET导入
xmlstr=”“”
12345
地面
大的
...
"""
root=ET.fromstring(xmlstr)
targets=root.find('targets'))
对于targets.findall('target')中的目标:
_id=target.find('id'))
如果_id不是None并且在_id.text中为“12345”:
目标。删除(目标)
打印ET.tostring(根目录)
+1即使它未经测试,因为它可能有效,或者至少是解决方案的99%。
tree = ET.parse('file.xml')
root = tree.getroot()
parent_map = dict((c, p) for p in tree.getiterator() for c in p)
# list so that we don't mess up the order of iteration when removing items.
iterator = list(root.getiterator('Target'))
for item in iterator:
old = item.find('ID')
text = old.text
if '12345' in text:
parent_map[item].remove(item)
continue
tree.write('out.xml')
#!/usr/bin/env python
import xml.etree.ElementTree as ET
xmlstr="""<Root>
<Stuff></Stuff>
<MoreStuff></MoreStuff>
<Targets>
<Target>
<ID>12345</ID>
<Type>Ground</Type>
<Size>Large</Size>
</Target>
<Target>
...
</Target>
</Targets>
</Root>"""
root = ET.fromstring(xmlstr)
targets = root.find('Targets')
for target in targets.findall('Target'):
_id = target.find('ID')
if _id is not None and '12345' in _id.text:
targets.remove(target)
print ET.tostring(root)