Python 访问列表中对象的属性
我正在使用一本名为《Python》的书,这本书的第8章(软件对象)中有一个挑战。我的代码可以工作,但我想为代码添加另一个功能;我需要添加什么代码来喂养/玩耍/与特定动物交谈 在我代码的choice#7(7-喂养特定的动物)中,我已经编写了一些代码,但不起作用。如何访问/更改用户选择的特定对象的属性 此外,是否有改进/缩短代码的反馈Python 访问列表中对象的属性,python,Python,我正在使用一本名为《Python》的书,这本书的第8章(软件对象)中有一个挑战。我的代码可以工作,但我想为代码添加另一个功能;我需要添加什么代码来喂养/玩耍/与特定动物交谈 在我代码的choice#7(7-喂养特定的动物)中,我已经编写了一些代码,但不起作用。如何访问/更改用户选择的特定对象的属性 此外,是否有改进/缩短代码的反馈 # Critter Caretaker # A virtual pet to care for class Critter(object): import r
# Critter Caretaker
# A virtual pet to care for
class Critter(object):
import random
"""A virtual pet"""
def __init__(self, name, hunger = random.randint(0,9), boredom = random.randint(0,11)):
self.name = name
self.hunger = hunger
self.boredom = boredom
def __pass_time(self):
self.hunger +=1
self.boredom +=1
def __str__(self):
m = "name is: {}, hunger is: {}, boredom is: {}".format(self.name, self.hunger,self.boredom)
return m
@property
def mood(self):
unhappiness = self.hunger + self.boredom
if unhappiness <5:
m = "happy"
elif 5 <= unhappiness <=10:
m = "okay"
elif 11 <= unhappiness <=15:
m = "frustrated"
else:
m= "mad"
return m
def talk(self):
print("I'm", self.name, "and I feel", self.mood, "now.\n")
self.__pass_time()
def eat(self, food=3):
print("Yummy! Thank you.")
self.hunger -=food
if self.hunger <0:
self.hunger = 0
self.__pass_time()
def play(self, fun=4):
print("That was fun! Thanks")
self.boredom -=fun
if self.boredom <0:
self.boredom = 0
self.__pass_time()
def main():
noc = []
noc.append(Critter("Chicken"))
print("An critter named Chicken has been created")
choice = None
while choice != "0":
print \
("""
Critter Caretaker
0 - Quit
1 - Listen to all your critters
2 - Feed all your critters
3 - Play with all your critters
4 - Create a new critter
5 - Show a list of critters
6 - Delete a critter
7 - Feed a specific critter
""")
choice = input("Choice: ")
print()
# exit
if choice == "0":
print("Good-bye.")
# listen to critters
elif choice == "1":
if len(noc) != 0:
i.talk()
else:
print("No critters exist")
# feed your critters
elif choice == "2":
if len(noc) != 0:
for i in noc:
print(i.name, "says:", end = " ")
i.eat()
# play with your critters
elif choice == "3":
if len(noc) != 0:
for i in noc:
print(i.name, "says:", end = " ")
i.play()
else:
print("No critter exists")
# Create a new critter
elif choice == "4":
noc.append(Critter(input("Enter a name for your new critter: ")))
# Show critters
elif choice =="5":
b = 0
if len(noc) != 0:
for i in noc:
b +=1
print(b, "." ,i.name)
else:
print("No critter exists")
# delete a critter
elif choice == "6":
a = int(input("Enter the serial number of critter you want to delete: "))
a = a -1
del noc[a]
# feed a specific critter
elif choice == "7":
sctd = input("Enter name of critter you want to feed: ")
if sctd in noc:
noc.eat()
else:
print("That critter doesn't exists")
# print attributes of critters
elif choice == "919":
for i in noc:
print(i)
else:
print("\nSorry, but", choice, "isn't valid.")
main()
("\n\nPress the enter key to exit.")
#动物管理员
#要照顾的虚拟宠物
类生物(对象):
随机输入
“虚拟宠物”
定义初始化(self,name,饥饿=random.randint(0,9),无聊=random.randint(0,11)):
self.name=名称
饥饿
无聊
定义通过时间(自身):
自我饥饿+=1
自我厌倦+=1
定义(自我):
m=“name是:{},饥饿是:{},无聊是:{}”。格式(self.name,self.饥饿,self.boredom)
返回m
@财产
情绪(自我):
不快乐=自我饥饿+自我厌倦
如果喂食特定生物的分支中存在不快乐,则行noc.eat()
--noc
是一个列表,其中没有eat()
方法。您需要访问输入指定的生物,并对该对象调用eat()
方法。比如:
for c in noc:
if c.name == sctd:
c.eat()
break
(尽管这个例子有一个问题,如果多个生物匹配sctd
——解决这个问题我将留给你)
关于代码的另一个次要反馈:docstring应该是定义中的第一条语句。只是一个小提示,我认为类似于import random
的约定可能应该放在开始处,而不是放在类中,这样也可以解决@nthall提出的问题也就是说,您的docstring当前不是第一个对象。这并不能回答这个问题。一旦你有足够的钱,你将能够;相反或者你想问?我不是在问一个问题,我只是有点含糊其辞,因为我对python规范在这个问题上只有90%的把握。