Python 使用切片以lastname、firstname格式创建新字符串
我已经完成了其他部分,我只是需要帮助,当用户输入全名时,将新的_string2格式化为姓、名。没有语法,它只显示名字和姓氏。谢谢大家!Python 使用切片以lastname、firstname格式创建新字符串,python,Python,我已经完成了其他部分,我只是需要帮助,当用户输入全名时,将新的_string2格式化为姓、名。没有语法,它只显示名字和姓氏。谢谢大家! def main(): full_name = input('Enter your full name: ') x = len(full_name) - 1 print("Your name backwards is: ") while(x >= 0): print(full_name[x], end="")
def main():
full_name = input('Enter your full name: ')
x = len(full_name) - 1
print("Your name backwards is: ")
while(x >= 0):
print(full_name[x], end="")
x -= 1
y = full_name.index("")
new_string2 = full_name[x+1:] + "" + full_name[0:y]
print("\n""Alphabetically, your name is", new_string2 )
new_string = full_name[x+1:] + "" + full_name[0:y]
d={"UPPER_CASE":0, "LOWER_CASE":0}
for c in full_name:
if c.isupper():
d["UPPER_CASE"]+=1
elif c.islower():
d["LOWER_CASE"]+=1
else:
pass
print ("Your name has" , d["UPPER_CASE"] , "upper case letters and " , d["LOWER_CASE"] , "lower case letters")
incorrect_string = "You have to be vewy, vewy twicky to twap a wascally wabbit"
correct_string = incorrect_string.replace('w', 'r')
print (correct_string)
main()
我只是假设姓氏总是在最后一个空格之后。而且不关心语法,只是修复了代码 替换这个
y = full_name.index("")
new_string2 = full_name[x+1:] + "" + full_name[0:y]
print("\n""Alphabetically, your name is", new_string2 )
为此:
y = full_name.split(" ")
new_string2 = y[-1:][0] + ", " + " ".join(y[:-1])
print("\n""Alphabetically, your name is", new_string2)
并删除更改后断开的以下行:
new_string = full_name[x+1:] + "" + full_name[0:y]
如果您喜欢在第一个空格前使用名字作为单词,请使用以下代码:
new_string2 = " ".join(y[1:]) + ", " + y[0]
只要小心,如果用户输入的名称没有任何空格,它将被打断(索引例外)。名字和姓氏将被空格分隔吗?给出输入和输出的例子。效果很好。非常感谢你!