Python 同一数字的乘法键

我使用的是python 3.5， 我需要将这个dict相乘，这应该输出dict每个键的相乘结果

{0: [0.0008726003490401396, 0.004363001745200698, 0.0008726003490401396, 0.0008726003490401396, 0.0017452006980802793, 0.008726003490401396, 0.0008726003490401396, 0.0017452006980802793, 0.0008726003490401396, 0.0017452006980802793, 0.0017452006980802793, 0.0008726003490401396, 0.0008726003490401396], 1: [0.007853403141361256, 0.008726003490401396, 0.0008726003490401396], 2: [0.004363001745200698, 0.0008726003490401396, 0.0008726003490401396, 0.0017452006980802793, 0.0008726003490401396, 0.0008726003490401396, 0.007853403141361256, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.002617801047120419, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.0017452006980802793, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.0017452006980802793, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.002617801047120419, 0.0008726003490401396, 0.0008726003490401396, 0.0017452006980802793, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.002617801047120419, 0.0034904013961605585, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.002617801047120419, 0.0008726003490401396, 0.0034904013961605585, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396, 0.0008726003490401396]}

这是我的尝试，但不起作用：

lista = {k: [v*v for v in v] for k, v in lista.items()}

例如，我将输出：

{0: [0.068726003490401396], 1: [0.077853403141361256, 2: [0.098363001745200698]}

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使用字典理解和+：

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与其理解内部列表，不如研究python的“reduce”函数谢谢你的回答..但是0.0008726003490401396*0.004363001745200698=不是MoltiApplication的结果..@DavideDiMenna，那么，你能详细说明预期值是如何计算的吗？你说得对！现在我试着去做。。没有导入不是一种方法吗？@DavideDiMenna，您可以用

lambda，b:a*b

替换

mul

。但是reduce应该在python3.x中导入。@DavideDiMenna，

reduce（…）

->

reduce（…）*0.5似乎是您想要的。
>>> from functools import mul
>>> mul(3, 4)  # == 3 * 4
12

>>> from functools import reduce
>>> reduce(mul, [3, 4, 2])  # == (3 * 4) * 2
24

>>> from functools import reduce
>>> from operator import mul
>>>
>>> lista = {
...     0: [0.0008726003490401396, 0.004363001745200698],
...     1: [0.007853403141361256, 0.008726003490401396, 0.0008726003490401396],
...     2: [0.004363001745200698, 0.0008726003490401396, 0.0008726003490401396],
... }
>>>
>>> {key: reduce(mul, value) for key, value in lista.items()}
{0: 3.8071568457248673e-06, 1: 5.979827506374137e-08, 2: 3.322126392430076e-09}
>>> {key: [reduce(mul, value)] for key, value in lista.items()}
{0: [3.8071568457248673e-06], 1: [5.979827506374137e-08], 2: [3.322126392430076e-09]}