Python 获取空白列表-不知道为什么？

我使用以下代码：

from __future__ import division
from __future__ import print_function

in_file = open("s:/Personal Folders/Andy/Python Projects/People Cancelled/Analyze Authorize Truncated.csv")
text = in_file.readlines()
in_file.close()

header = text[0:1]
text = text[1:]

for index, line in enumerate(text):
    text[index] = line.split(",")

name = text
dates = text

for index, line in enumerate(name):
    name[index] = line[3:5]

for stuff, area in enumerate(dates):
     dates[stuff] = area[7:8]

print(name)
print(dates)

我得到这个输出：

 [[], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], []]
 [[], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], []]

知道为什么吗？出于某种原因，两个For循环之间似乎存在某种干扰-如果我单独执行其中一个，我将得到我想要的结果

---

谢谢

看看这两行：

name = text
date = text

---

这些行不复制要指向的名称和日期文本；相反，它们将名称和日期本质上都设置为文本的备用名称。因此，在第三个for循环（body

name[index]=line[3:5]

之后，

text

中的每一行都有两个项目长（因为

text

和

name

是相同的列表）。事实上，我甚至不明白为什么您最初将

名称

和

日期

设置为

文本

；只需将

名称

和

日期

设置为新的空列表，并根据

文本

向其添加项目，即可实现预期的结果。您能给我们一个输入数据的示例吗？啊，doh，这很有意义！我必须想办法如何将旧列表中的值附加到新列表中，但这应该不会太难。实际上，我还可以获取一段文本（即文本[：]）而且工作列表应该有一个方法

append

——看起来应该是完美的。或者，您可以使用列表理解来根据旧列表定义新列表，比如

name=[line[3:5]表示文本中的行]