python中的Diff多维字典
我有两本字典python中的Diff多维字典,python,Python,我有两本字典 a = {'home': {'name': 'Team1', 'score': 0}, 'away': {'name': 'Team2', 'score': 0}} b = {'home': {'name': 'Team1', 'score': 2}, 'away': {'name': 'Team2', 'score': 0}} 钥匙永远不会变,但我想知道['home']['score']已经变了 有什么简单的方法可以做到这一点吗?作为下意识的初始反应: a = {'home':
a = {'home': {'name': 'Team1', 'score': 0}, 'away': {'name': 'Team2', 'score': 0}}
b = {'home': {'name': 'Team1', 'score': 2}, 'away': {'name': 'Team2', 'score': 0}}
钥匙永远不会变,但我想知道['home']['score']已经变了
有什么简单的方法可以做到这一点吗?作为下意识的初始反应:
a = {'home': {'name': 'Team1', 'score': 0}, 'away': {'name': 'Team2', 'score': 0}}
b = {'home': {'name': 'Team1', 'score': 2}, 'away': {'name': 'Team2', 'score': 0}}
def valchange(d1, d2, parent=''):
changes=[]
for k in d1.keys():
if type(d1[k])==type({}):
changes.extend(valchange(d1[k], d2[k], k))
else:
if d1[k]!=d2[k]:
if parent=='':
changes.append(k + ' has changed ')
else:
changes.append(parent + '.' + k + ' has changed')
return changes
print valchange(a,b)
>>>
['home.score has changed']
这里有一个非常简单的解决方案。它返回一个列表列表,其中包含不同元素的所有第一级和第二级字典键。希望这就是你想要的:)
干杯 我不确定这是否是您需要的,但我发现了一个库,它可以产生python数据结构之间的差异。它被称为,它给你提供了两本字典之间所有不同的丰富内容。我不确定如果它给了你不同的“商店”,也许它会显示一个不同的价值为整个“家”条目。您必须尝试一下。您可以使用我的python软件包: 它处理的不仅仅是递归字典差异: 装置 从PyPi安装:
pip install deepdiff
如果您是Python3,还需要安装:
pip install future six
示例用法
同一对象返回空
>>> t1 = {1:1, 2:2, 3:3}
>>> t2 = t1
>>> ddiff = DeepDiff(t1, t2)
>>> print (ddiff.changes)
{}
项目的类型已更改
>>> t1 = {1:1, 2:2, 3:3}
>>> t2 = {1:1, 2:"2", 3:3}
>>> ddiff = DeepDiff(t1, t2)
>>> print (ddiff.changes)
{'type_changes': ["root[2]: 2=<type 'int'> vs. 2=<type 'str'>"]}
>>> t1 = {1:1, 2:2, 3:3}
>>> t2 = {1:1, 2:4, 3:3}
>>> ddiff = DeepDiff(t1, t2)
>>> print (ddiff.changes)
{'values_changed': ['root[2]: 2 ====>> 4']}
添加和/或删除的项目
>>> t1 = {1:1, 2:2, 3:3, 4:4}
>>> t2 = {1:1, 2:4, 3:3, 5:5, 6:6}
>>> ddiff = DeepDiff(t1, t2)
>>> pprint (ddiff.changes)
{'dic_item_added': ['root[5, 6]'],
'dic_item_removed': ['root[4]'],
'values_changed': ['root[2]: 2 ====>> 4']}
弦差
>>> t1 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":"world"}}
>>> t2 = {1:1, 2:4, 3:3, 4:{"a":"hello", "b":"world!"}}
>>> ddiff = DeepDiff(t1, t2)
>>> pprint (ddiff.changes, indent = 2)
{ 'values_changed': [ 'root[2]: 2 ====>> 4',
"root[4]['b']:\n--- \n+++ \n@@ -1 +1 @@\n-world\n+world!"]}
>>>
>>> print (ddiff.changes['values_changed'][1])
root[4]['b']:
---
+++
@@ -1 +1 @@
-world
+world!
>>> t1 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 2, 3]}}
>>> t2 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 2]}}
>>> ddiff = DeepDiff(t1, t2)
>>> pprint (ddiff.changes, indent = 2)
{ 'list_removed': ["root[4]['b']: [3]"]}
字符串差2
>>> t1 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":"world!\nGoodbye!\n1\n2\nEnd"}}
>>> t2 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":"world\n1\n2\nEnd"}}
>>> ddiff = DeepDiff(t1, t2)
>>> pprint (ddiff.changes, indent = 2)
{ 'values_changed': [ "root[4]['b']:\n--- \n+++ \n@@ -1,5 +1,4 @@\n-world!\n-Goodbye!\n+world\n 1\n 2\n End"]}
>>>
>>> print (ddiff.changes['values_changed'][0])
root[4]['b']:
---
+++
@@ -1,5 +1,4 @@
-world!
-Goodbye!
+world
1
2
End
改型
>>> t1 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 2, 3]}}
>>> t2 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":"world\n\n\nEnd"}}
>>> ddiff = DeepDiff(t1, t2)
>>> pprint (ddiff.changes, indent = 2)
{ 'type_changes': [ "root[4]['b']: [1, 2, 3]=<type 'list'> vs. world\n\n\nEnd=<type 'str'>"]}
列表差异2:注意它不考虑顺序
>>> # Note that it DOES NOT take order into account
... t1 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 2, 3]}}
>>> t2 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 3, 2]}}
>>> ddiff = DeepDiff(t1, t2)
>>> pprint (ddiff.changes, indent = 2)
{ }
包含字典的列表:
>>> t1 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 2, {1:1, 2:2}]}}
>>> t2 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 2, {1:3}]}}
>>> ddiff = DeepDiff(t1, t2)
>>> pprint (ddiff.changes, indent = 2)
{ 'dic_item_removed': ["root[4]['b'][2][2]"],
'values_changed': ["root[4]['b'][2][1]: 1 ====>> 3"]}
你能详细说明你想做什么吗?我想尝试一下:)为什么不将这些值封装到一个单独的类中呢?我想比较两个字典,找出哪个键是改变的键。。因此,在示例b中,['home']['score']从0更改为2,因此我想知道是['home']['score']更改了注意,
的用法等同于=代码>。自发布后,标准已更改。
>>> # Note that it DOES NOT take order into account
... t1 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 2, 3]}}
>>> t2 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 3, 2]}}
>>> ddiff = DeepDiff(t1, t2)
>>> pprint (ddiff.changes, indent = 2)
{ }
>>> t1 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 2, {1:1, 2:2}]}}
>>> t2 = {1:1, 2:2, 3:3, 4:{"a":"hello", "b":[1, 2, {1:3}]}}
>>> ddiff = DeepDiff(t1, t2)
>>> pprint (ddiff.changes, indent = 2)
{ 'dic_item_removed': ["root[4]['b'][2][2]"],
'values_changed': ["root[4]['b'][2][1]: 1 ====>> 3"]}