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python脚本在ZMQ recv()中超时后未终止_Python_Linux_Python 3.x_Zeromq_Pyzmq - Fatal编程技术网

python脚本在ZMQ recv()中超时后未终止

python脚本在ZMQ recv()中超时后未终止,python,linux,python-3.x,zeromq,pyzmq,Python,Linux,Python 3.x,Zeromq,Pyzmq,到目前为止,这是我第一次使用IPC,我编写了以下脚本: #!/usr/bin/python import zmq context = zmq.Context() socket = context.socket(zmq.PAIR) socket.setsockopt(zmq.RCVTIMEO, 2000) socket.connect ("ipc:///tmp/something") socket.send(b"123") try: message = socket.recv() ex

到目前为止,这是我第一次使用IPC,我编写了以下脚本:

#!/usr/bin/python

import zmq

context = zmq.Context()
socket = context.socket(zmq.PAIR)
socket.setsockopt(zmq.RCVTIMEO, 2000)
socket.connect ("ipc:///tmp/something")
socket.send(b"123")
try:
    message = socket.recv()
except:
    print("DEBUG!")
    message = None
当我的服务器脚本运行时(它只是发送一个答案),一切都正常

但是当
.recv()
调用超时时(例如,因为没有服务器运行),脚本在“DEBUG!”-打印后不会终止,我必须使用Ctrl+C手动停止脚本

我试着断开和关闭插座,但没有任何改变

当我将整个脚本放入一个函数并调用它时,我在键盘中断上得到以下错误:

^CException ignored in: <bound method Context.__del__ of <zmq.sugar.context.Context object at 0x7f16a36d5128>>
Traceback (most recent call last):
  File "/usr/lib/python3.6/site-packages/zmq/sugar/context.py", line 46, in __del__
    self.term()
  File "zmq/backend/cython/context.pyx", line 136, in zmq.backend.cython.context.Context.term (zmq/backend/cython/context.c:2339)
  File "zmq/backend/cython/checkrc.pxd", line 12, in zmq.backend.cython.checkrc._check_rc (zmq/backend/cython/context.c:3207)
KeyboardInterrupt
^CEException在以下位置被忽略:
回溯(最近一次呼叫最后一次):
文件“/usr/lib/python3.6/site packages/zmq/sugar/context.py”,第46行,在__
self.term()
文件“zmq/backend/cython/context.pyx”,第136行,位于zmq.backend.cython.context.term(zmq/backend/cython/context.c:2339)中
文件“zmq/backend/cython/checkrc.pxd”,第12行,在zmq.backend.cython.checkrc.\u check\u rc(zmq/backend/cython/context.c:3207)中
键盘中断
我正在Arch Linux上运行Python 3.6.1和PyZMQ模块的16.0.2版。

可以将其作为标准的ZeroMQ基础设施设置策略:
LINGER
属性的默认值强制
套接字
实例在尝试
.close()
时等待。因此,将其设置为
0
,以便在实例化时避免此功能/行为,而不是最终在终止时挂起

import zmq
nIOthreads = 2                           # ____POLICY: set 2+: { 0: non-blocking, 1: blocking, 2: ...,  }
context = zmq.Context( nIOthreads )      # ____POLICY: set several IO-datapumps

socket  = context.socket( zmq.PAIR )
socket.setsockopt( zmq.LINGER,      0 )  # ____POLICY: set upon instantiations
socket.setsockopt( zmq.AFFINITY,    1 )  # ____POLICY: map upon IO-type thread
socket.setsockopt( zmq.RCVTIMEO, 2000 )

socket.connect( "ipc:///tmp/something" )
socket.send( b"123" )
try:
    message = socket.recv()
except:
    print( "DEBUG!" )
    message = None
finally:
    socket.close()                       # ____POLICY: graceful termination
    context.term()                       # ____POLICY: graceful termination

user3666197的答案是正确的,因为
socket.setsockopt(zmq.LINGER,0)
将解决您描述的问题

但每对套接字仅用于单个进程中的线程间通信。特别是,当连接断开时,它不会重新连接

它可以通过ipc正常工作(我从未尝试过),但我建议使用不同的套接字类型