Python 如何在IPyWidget上创建自我感知按钮
我需要编写一个函数,知道单击哪个按钮调用它。我正在使用ipywidgets和jupyter笔记本 以下是一些示例代码:Python 如何在IPyWidget上创建自我感知按钮,python,jupyter-notebook,ipywidgets,Python,Jupyter Notebook,Ipywidgets,我需要编写一个函数,知道单击哪个按钮调用它。我正在使用ipywidgets和jupyter笔记本 以下是一些示例代码: import ipywidgets as widgets button1 = widgets.Button(description = 'I am button 1') button2 = widgets.Button(description = 'I am button 2') def self_aware(caller): # Some code I don't
import ipywidgets as widgets
button1 = widgets.Button(description = 'I am button 1')
button2 = widgets.Button(description = 'I am button 2')
def self_aware(caller):
# Some code I don't know
pass
button1.on_click(self_aware)
button2.on_click(self_aware)
widgets.VBox([button1, button2])
单击按钮1时,应将其作为参数传递给self\u aware
函数。
例如,仅打印('I am button 1')或2就足够了您可以访问按钮说明:
def self_aware(caller):
print(caller.description)
也许
print(caller.description)
Thank you drops,这就解决了问题!