Python 数组中字符串之间的公共字符

我试图在数组中的字符串之间找到公共字符。为此，我使用了一个hashmap，它被定义为Counter。在多次尝试后，我无法获得正确的答案。我在这里做错了什么

预期Ans:{（c，1），（o，1）}

我得到的：{（'c'，1）}

我的代码：

arr  = ["cool","lock","cook"]


def Counter(arr):
    d ={}
    for items in arr:
        if items not in d:
            d[items] = 0
        d[items] += 1
    return d

res = Counter(arr[0]).items()

for items in arr:
    res &= Counter(items).items()

print(res)

尝试使用和：

尝试使用和：

---

没有任何其他库的方法可能是这样的：

arr = ["cool","lock","cook"] 

def Counter(obj_str):
    countdict = {x: 0 for x in set(obj_str)}
    for char in obj_str:
            countdict[char] += 1
    return {(k, v) for k,v in countdict.items()}

print(Counter(arr[0]))

---

这将为您提供所需格式的结果。

没有任何其他库的方法可能是这样的：

arr = ["cool","lock","cook"] 

def Counter(obj_str):
    countdict = {x: 0 for x in set(obj_str)}
    for char in obj_str:
            countdict[char] += 1
    return {(k, v) for k,v in countdict.items()}

print(Counter(arr[0]))

In [29]: from collections import Counter

In [30]: words = ["cool","coccoon","cook"]

In [31]: chars = ''.join(set(''.join(words)))

In [32]: counts = [Counter(w) for w in words]

In [33]: common = {ch: min(wcount[ch] for wcount in counts) for ch in chars}

In [34]: answer  = {ch: count for ch, count in common.items() if count}

In [35]: answer
Out[35]: {'c': 1, 'o': 2}

In [36]: 

---

这将为您提供所需格式的结果。

记住向已回答的人反馈。记住向已回答的人反馈。

In [29]: from collections import Counter

In [30]: words = ["cool","coccoon","cook"]

In [31]: chars = ''.join(set(''.join(words)))

In [32]: counts = [Counter(w) for w in words]

In [33]: common = {ch: min(wcount[ch] for wcount in counts) for ch in chars}

In [34]: answer  = {ch: count for ch, count in common.items() if count}

In [35]: answer
Out[35]: {'c': 1, 'o': 2}

In [36]: