Python 添加需要3个参数而不仅仅是key/value的\u头

我遇到以下错误消息：

TypeError:add\u header（）正好接受3个参数（给定2个）

使用这些参数时：

testService（“SomeServiceName”、“POST”、“[redated valid url]”、（'Content-type'、'application/json'）、[redated valid json]）

通常，这个错误意味着我没有将“self”作为参数传递，但是由于这个方法不是在类中调用的，我不知道该怎么办。我尝试将self作为参数传入参数和方法内部。我试着把标题用括号和括号括起来。当我传递“self”时，我得到错误消息self未定义，当我使用括号而不是括号时，我得到与上面相同的错误

有谁有神奇的Python调试技能吗？非常感谢您抽出时间来查看此信息

def testService(name, verb, url, header="", requestBody=""):

#Log out the name of the request we're testing
if (name is not None) or (name.strip() is not ""):
    print "Checking  " + name + "\n\n"

    # Make URL with StoreNumber
    if (url is not None) or (url is not ""):
        testUrl = url

        # If specified verb is GET
        if verb.strip().upper() == "GET":

            # Create request
            req = urllib2.Request(testUrl)
            print "Making request with URL: " + testUrl + "\n\n"

            # Send request
            try:
                response = urllib2.urlopen(req)

                # If service returns 200 Okay
                print "Connection to " + name + " Service successful. Returned with code " + str(response.code) + "\n\n"

                # Log response
                print "Response: " + response.read() + "\n\n"


                # Handle exceptions
                # If HTTP Error
            except HTTPError as e:
                if hasattr(e, 'reason'):
                    print name + ' failed to reach a server.'
                    print 'Reason: ', e.reason

                elif hasattr(e, 'code'):
                    print e.code

                elif hasattr(e, 'message'):
                    print e.message
                pass 

            # If URL was the problem
            except URLError as e:
                if hasattr(e, 'reason'):
                    print name + ' failed to reach a server.'

                    if str(e.reason) == "[Errno 11004] getaddrinfo failed":
                        print "[Errno 11004] getaddrinfo failed with bad url: " + testUrl + "\n\n"

                    else:
                        print 'Reason: ', e.reason

                elif hasattr(e, 'code'):
                    print 'Error code: ', e.code

                elif hasattr(e, 'message'):
                    print e.message
                pass 


        # If specified verb was POST
        elif verb.strip().upper() == "POST":

            # Check for None requestBody
            if (requestBody is not None) or (requestBody.strip() is not ""):
                data = urllib.urlencode(requestBody)

                # Create request
                req = urllib2.Request(testUrl, data)

                # Check for header
                if (header is not None) or (header.strip() is not ""):
                    req.add_header(header)

                    # YO YO THE BELOW CODE IS INCOMPLETE PLEASE FINISH
                    # Log request with URL and Data
                    print "Making request with URL: " + testUrl + " and data: THIS PART IS UNFINISHED PLEASE FINISH ME \n\n" 

                    try: 
                        response = urllib2.urlopen(req)

                        # If service returns 200 Okay
                        print "Connection to " + name + " Service successful. Returned with code " + str(response.code) + "\n\n"

                        # Log response
                        print "Response: " + response.read() + "\n\n"


                    # Handle exceptions
                    # If HTTP Error
                    except HTTPError as e:
                        if hasattr(e, 'code'):
                            print e.code
                        elif hasattr(e, 'message'):
                            print e.message
                        elif hasattr(e, 'reason'):
                            print name + ' failed to reach a server.'
                            print 'Reason: ', e.reason
                        pass 

                    except URLError as e:
                        if hasattr(e, 'reason'):
                            print name + ' failed to reach a server.'

                            if str(e.reason) == "[Errno 11004] getaddrinfo failed":
                                print "[Errno 11004] getaddrinfo failed with bad url: " + url + "\n\n"
                            else:
                                print 'Reason: ', e.reason                
                        elif hasattr(e, 'code'):
                            print 'Error code: ', e.code

                        elif hasattr(e, 'message'):
                            print e.message
                        pass 

                # Header non-existent in testService call
                else: 
                    print "Service header not provided. Exiting program"
                    sys.exit() 

            # Requesty Body not present in testService call
            else:
                print "Service request body not provided in code. Exiting program"
                sys.exit()

        # If specified verb is not supported (Currently only GET and POST are supported)    
        else:
            print name + " Service written with HTTP verb other than GET or POST. Exiting program"
            sys.exit()

    else:
        print "Service url not provided in code. Exiting program"
        sys.exit() 


else: 
    print "Service name not provided in code. Exiting program"
    sys.exit()

从中，

add_头

接受两个参数。您使用一个参数调用它，一个具有两个值的元组

你应该做什么：

req.add_header(key, value)

您当前正在执行的操作，因为您将头作为元组获取：

req.add_header((key, value,))    # aka passing a tuple with both arguments to the key parameter

您需要解压缩元组：

req.add_header(header[0], header[1])

或者更好地使用运算符（

*

）：

---

此外，您正在使用空字符串作为

标题

的默认参数，当提供它时，它是一个元组。您可能应该将默认值更改为元组或

None

您的

标题是一个2元组：

('Content-Type', 'application/json')

您正在尝试这样做：

req.add_header('Content-Type', 'application/json')

但实际上，你正在这样做：

req.add_header(('Content-Type', 'application/json'))

请注意，您只传递了一个参数——一个元组，而不是两个，一个键和一个值

若要修复此问题，请在使用
*
（非正式的“splat”）操作符传递
标题时，将其解压缩：

req.add_header(*header)

请查看文档：

虽然函数需要一个键和一个值，但只传递一个对象。因为您是在req对象上调用它，所以也传递了隐式的“self”

您可以通过两种方式调用此函数：

req.add_header(key, value)
urllib2.Request.add_header(req, key, value) # explicitly passing the reference instead of self

我不确定您是否希望传递的字符串被视为键或值，但添加另一个参数（或使header参数采用dict，然后在for循环中适当拆分）应该可以解决这个问题。例如（删除了不相关的代码）：

工作完美。非常感谢你！我喜欢splat操作符。
req.add_header(key, value)
urllib2.Request.add_header(req, key, value) # explicitly passing the reference instead of self

def testService(name, verb, url, header=None, requestBody=""):

    if header is None:
         header = {}

    for key, value in header.iteritems():
        req.add_header(key, value)