如何将列表中的前三个元素设置为列,其余元素设置为行-Python
我有上面的dataframe,我想按如下方式拆分Detail列: 在Python中如何实现这一点 感谢您的帮助。自定义功能 我使用了如何将列表中的前三个元素设置为列,其余元素设置为行-Python,python,pandas,dataframe,multi-index,Python,Pandas,Dataframe,Multi Index,我有上面的dataframe,我想按如下方式拆分Detail列: 在Python中如何实现这一点 感谢您的帮助。自定义功能 我使用了np.重塑,因为我已经习惯了。然而,这可以完成同样的事情 def process_details(details): cols, *data = np.reshape(details, (-1, 3)) return pd.DataFrame(data, columns=cols) 肩并肩 因为列名不匹配 def process_details
np.重塑,因为我已经习惯了。然而,这可以完成同样的事情
def process_details(details):
cols, *data = np.reshape(details, (-1, 3))
return pd.DataFrame(data, columns=cols)
肩并肩
因为列名不匹配
def process_details(details):
cols, *data = zip(*[iter(details)] * 3)
return pd.DataFrame(data, columns=cols)
但是如果你坚持把它们堆起来
pd.concat({
cat: process_details(details)
for cat, details in zip(*map(df.get, df))
}, sort=False, axis=1)
Animal Food
Name Predator? Habitat Name Color Sweet?
0 Tigers Yes Forests Bread Brown No
1 Lions Yes Savanna Rice White No
2 Deers No Hardwoods Sushi N/A No
非常感谢你的回答。很高兴学习创建一个函数来完成这项工作。
pd.concat({
cat: process_details(details)
for cat, details in zip(*map(df.get, df))
}, sort=False, axis=1)
Animal Food
Name Predator? Habitat Name Color Sweet?
0 Tigers Yes Forests Bread Brown No
1 Lions Yes Savanna Rice White No
2 Deers No Hardwoods Sushi N/A No
pd.concat({
cat: process_details(details)
for cat, details in zip(*map(df.get, df))
}, sort=False)
Name Predator? Habitat Color Sweet?
Animal 0 Tigers Yes Forests NaN NaN
1 Lions Yes Savanna NaN NaN
2 Deers No Hardwoods NaN NaN
Food 0 Bread NaN NaN Brown No
1 Rice NaN NaN White No
2 Sushi NaN NaN N/A No