Python 创建lxml元素子类的困难

我试图创建元素类的一个子类。但我在开始时遇到了麻烦

from lxml import etree
try:
    import docx
except ImportError:
    from docx import docx

class File(etree.ElementBase):
    def _init(self):
        etree.ElementBase._init(self)
        self.body = self.append(docx.makeelement('body'))

f = File()
relationships = docx.relationshiplist()
title    = 'File' 
subject  = 'A very special File'
creator  = 'Me'
keywords = ['python', 'Office Open XML', 'Word']
coreprops = docx.coreproperties(title=title, subject=subject, creator=creator,
    keywords=keywords)
appprops = docx.appproperties()
contenttypes = docx.contenttypes()
websettings = docx.websettings()
wordrelationships = docx.wordrelationships(relationships)
docx.savedocx(f, coreprops, appprops, contenttypes, websettings,
wordrelationships, 'file.docx')

---

当我尝试打开从该代码输出的文档时，我的Word版本（带兼容包的2003）出现以下错误：“此文件是由Word 2007的早期beta版创建的，无法在此版本中打开。”当我使用使用docx.newdocument（）创建的其他元素替换文件对象时，这份文件很好。有什么想法/建议吗？

我真的不明白为什么要使用名为File的单独类

正如Michael0x2a所说，您没有放置文档标记，因此它不会工作（我认为Word 2007也无法读取您的文件）

但下面是正确的代码：

from lxml import etree
try:
    import docx
except ImportError:
    from docx import docx

class File(object):
    def makeelement(tagname, tagtext=None, nsprefix='w', attributes=None,
                    attrnsprefix=None):
        '''Create an element & return it'''
        # Deal with list of nsprefix by making namespacemap
        namespacemap = None
        if isinstance(nsprefix, list):
            namespacemap = {}
            for prefix in nsprefix:
                namespacemap[prefix] = nsprefixes[prefix]
            # FIXME: rest of code below expects a single prefix
            nsprefix = nsprefix[0]
        if nsprefix:
            namespace = '{'+nsprefixes[nsprefix]+'}'
        else:
            # For when namespace = None
            namespace = ''
        newelement = etree.Element(namespace+tagname, nsmap=namespacemap)
        # Add attributes with namespaces
        if attributes:
            # If they haven't bothered setting attribute namespace, use an empty
            # string (equivalent of no namespace)
            if not attrnsprefix:
                # Quick hack: it seems every element that has a 'w' nsprefix for
                # its tag uses the same prefix for it's attributes
                if nsprefix == 'w':
                    attributenamespace = namespace
                else:
                    attributenamespace = ''
            else:
                attributenamespace = '{'+nsprefixes[attrnsprefix]+'}'

            for tagattribute in attributes:
                newelement.set(attributenamespace+tagattribute,
                               attributes[tagattribute])
        if tagtext:
            newelement.text = tagtext
        return newelement

    def __init__(self):
        super(File,self).__init__()
        self.document = self.makeelement('document')
        self.document.append(self.makeelement('body'))


f = File()
relationships = docx.relationshiplist()
title    = 'File' 
subject  = 'A very special File'
creator  = 'Me'
keywords = ['python', 'Office Open XML', 'Word']
coreprops = docx.coreproperties(title=title, subject=subject, creator=creator,
    keywords=keywords)
appprops = docx.appproperties()
contenttypes = docx.contenttypes()
websettings = docx.websettings()
wordrelationships = docx.wordrelationships(relationships)
docx.savedocx(f.document, coreprops, appprops, contenttypes, websettings,
wordrelationships, 'file.docx')

---

你的意思是使用

\uuuu init\uuuu

而不是

\u init

作为构造函数吗？此外，您还可以尝试检查docx.newdocument（）以查看输出应该是什么样子。看起来您缺少了一个

document

标记，虽然这只是我的猜测。谢谢，但问题似乎来自元素类不喜欢init，因此简单的构造函数方法似乎不起作用。为什么要扩展Etree.ElementBase？