Python Discord.py在member.server\u default\u通道内的参数无效

我现在的代码是

@client.event
async def on_member_join(member):
    serverchannel = member.server.default_channel
    msg = "Wuss poppin', {0}. Welcome to {1}".format(member.mention, member.server.name)
    await client.send_message(member.server.default_channel, msg)`

@client.event
async def on_member_remove(member):
    serverchannel = member.server.default_channel
    msg = "Well. Cya, {0}!".format(member.mention)
    await client.send_message(serverchannel, msg)

以及其他必要的行（如

导入discord

等）和其他命令

当成员加入或离开时，我会出现以下错误：

Ignoring exception in on_member_join
Traceback (most recent call last):
  File "C:\Users\WillL\AppData\Local\Programs\Python\Python36\lib\site-packages\discord\client.py", line 307, in _run_event
    yield from getattr(self, event)(*args, **kwargs)
  File "C:/Users/WillL/Desktop/MemzBot-master/index.py", line 102, in on_member_join
    await client.send_message(member.server.default_channel, msg)
  File "C:\Users\WillL\AppData\Local\Programs\Python\Python36\lib\site-packages\discord\client.py", line 1145, in send_message
    channel_id, guild_id = yield from self._resolve_destination(destination)
  File "C:\Users\WillL\AppData\Local\Programs\Python\Python36\lib\site-packages\discord\client.py", line 289, in _resolve_destination
    raise InvalidArgument(fmt.format(destination))
discord.errors.InvalidArgument: Destination must be Channel, PrivateChannel, User, or Object. Received NoneType

---

我不明白为什么，我错过了什么？

默认频道不再是一件事了。

。这意味着两件事：

服务器。默认\u频道

可能返回非类型

试图向

服务器发送消息

可能会引起

不一致。找不到

这些情况将发生在8月3日之后创建的任何服务器上，或者任何已删除其“默认”频道的服务器上

您需要自己选择频道，或者要求服务器为欢迎消息设置频道。您仍然可以尝试发送到服务器，但如果发送失败，请确保有一个回退选项