Python 初学者';猜猜我的号码';节目。当猜测到正确的数字或超出猜测范围时,循环不会中断
因此,我正在学习python,我正在尝试编写一个简单的猜我的数字游戏,在这个游戏中,你只能猜5次,否则游戏就结束了。我真的有麻烦的while循环没有意识到数字已经猜测或猜测极限已经达到。还有没有更好的方法来格式化我的函数呢。感谢您第一次使用本网站时提供的所有帮助Python 初学者';猜猜我的号码';节目。当猜测到正确的数字或超出猜测范围时,循环不会中断,python,Python,因此,我正在学习python,我正在尝试编写一个简单的猜我的数字游戏,在这个游戏中,你只能猜5次,否则游戏就结束了。我真的有麻烦的while循环没有意识到数字已经猜测或猜测极限已经达到。还有没有更好的方法来格式化我的函数呢。感谢您第一次使用本网站时提供的所有帮助 # Guess my number # # The computer picks a random number between 1 and 100 # The player tries to guess it and the comp
# Guess my number
#
# The computer picks a random number between 1 and 100
# The player tries to guess it and the computer lets
# the player know if the guess is too high, too low
# or right on the money
import random
GUESS_LIMIT = 5
# functions
def display_instruct():
"""Display game instructions."""
print("\tWelcome to 'Guess My Number'!")
print("\nI'm thinking of a number between 1 and 100.")
print("Try to guess it in as few attempts as possible.")
print("\nHARDCORE mode - You have 5 tries to guess the number!\n")
def ask_number(question, low, high, step = 1):
"""Ask for a number within a range."""
response = None
while response not in range(low, high, step):
response = int(input(question))
return response
def guessing_loop():
the_number = random.randint(1, 100)
guess = ask_number("\nTake a guess:", 1, 100)
tries = 1
while guess != the_number or tries != GUESS_LIMIT:
if guess > the_number:
print("Lower...")
else:
print("Higher...")
guess = ask_number("Take a guess:", 1, 100)
tries += 1
if tries == GUESS_LIMIT:
print("\nOh no! You have run out of tries!")
print("Better luck next time!")
else:
print("\nYou guessed it! The number was", the_number)
print("And it only took you", tries, "tries!")
def main():
display_instruct()
guessing_loop()
# start the program
main()
input("\n\nPress the enter key to exit")
只要你没有达到猜测极限,你的while条件就是真的
while guess != the_number or tries != GUESS_LIMIT:
您应该将这些条件与
和
合并,而不是或
。按照现在的方式,整个条件将为真,因为尝试!=GUESS\u LIMIT
为真,即使GUESS!=_编号
为假。或者您可以使用break
语句显式中断周期。但从某种意义上说,前面的答案更为正确,您应该真正理解为循环设置的条件。您的或需要是和。