Python 查找最大值并过滤第一个值

我使用argrelextrema查找列表中的最大值

import  pandas as pd
from scipy.signal import argrelextrema
import numpy as np
noise_filter = 3
numbers = pd.Series ([101.5,100,101.1,99,105,22,21,20, 19]).to_numpy()
res = argrelextrema(numbers, np.greater_equal, order = noise_filter, mode = 'clip')[0]
print (res)

在本例中，它返回

[0 4]

如果索引小于noise\u filter，我想对其进行筛选。
因此0将被过滤

我怎样才能做到内线

 res = argrelextrema(numbers, np.greater_equal, order = noise_filter, mode = 'clip')[0]

所以看起来像

res = argrelextrema(numbers, np.greater_equal & (index > noise_filter), order = noise_filter, mode = 'clip')[0]

简单的决定，当我做切片的res

res = res[noise_filter:]

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不适合我。

如果你想过滤噪音过滤器下面的所有东西

filtered = [n for n in res if n > noise_filter]