Python Twilio可编程语音呼叫立即完成
我正在使用带有Swift和Python的新的Twilio可编程语音SDK。我已经开始了各自的快速启动项目，并且在大多数情况下，这些项目都是有效的。我能够获得一个有效的访问令牌，我能够成功地创建一个呼叫，我甚至能够接收呼叫。问题出在打电话的那一方 当我试图通过Swift SDK拨打电话时，电话在另一端开始响之前就断开了 我在Twilio文档中读到，Python Twilio可编程语音呼叫立即完成,python,ios,twilio,Python,Ios,Twilio,我正在使用带有Swift和Python的新的Twilio可编程语音SDK。我已经开始了各自的快速启动项目，并且在大多数情况下，这些项目都是有效的。我能够获得一个有效的访问令牌，我能够成功地创建一个呼叫，我甚至能够接收呼叫。问题出在打电话的那一方 当我试图通过Swift SDK拨打电话时，电话在另一端开始响之前就断开了 我在Twilio文档中读到，client.calls.create函数将立即返回完成状态，如果您不处理status\u回调事件。我曾尝试添加此项，但每次添加时，都会出现一个错误，即
client.calls.createstatus\u回调status\u回调client.calls.create@app.route('/outgoing', methods=['GET', 'POST'])
def outgoing():
account_sid = os.environ.get("ACCOUNT_SID", ACCOUNT_SID)
api_key = os.environ.get("API_KEY", API_KEY)
api_key_secret = os.environ.get("API_KEY_SECRET", API_KEY_SECRET)
from_number = [HARD_CODED_PHONE_NUMBER_FOR_CALLER]
to_number = [HARD_CODED_PHONE_NUMBER_FOR_RECIPIENT]
client = Client(api_key, api_key_secret, account_sid)
call = client.calls.create(url='http://twimlets.com/holdmusic?Bucket=com.twilio.music.ambient', to=to_number, from_=from_number)
# return str(call.sid)
resp = twilio.twiml.Response()
resp.say("Thank you for calling");
return str(resp)
class VoiceManager: NSObject, PKPushRegistryDelegate, TVONotificationDelegate, TVOCallDelegate, AVAudioPlayerDelegate {
//MARK: - Singleton
static let sharedManager = VoiceManager()
//MARK: - Private Constants
private let baseURLString = [MY_WEBAPP_ENDPOINT]
private let accessTokenEndpoint = "/accessToken"
//MARK: - Private Variables
private var deviceTokenString:String?
private var callInvite: TVOCallInvite?
private var call: TVOCall?
private var status: VoiceStatus = .idle
//MARK: - Getters
private func fetchAccessToken() -> String? {
guard let accessTokenURL = URL(string: baseURLString + accessTokenEndpoint) else {
return nil
}
return try? String.init(contentsOf: accessTokenURL, encoding: .utf8)
}
func placeCall(withParameters params: VoiceParameters, completion: @escaping (_ success: Bool, _ error: VAError?) -> Void) {
if (call != nil) {
call?.disconnect()
completion(false, .phoneCallInProgress)
status = .callEnded
hideActiveCallUI()
} else {
guard let accessToken = fetchAccessToken() else {
completion(false, .phoneAccessTokenFetchFailed)
return
}
guard let paramsDict = params.toDictionary() else {
completion(false, .phoneAccessTokenFetchFailed)
return
}
playOutgoingRingtone(completion: { [weak self] in
if let strongSelf = self {
strongSelf.call = VoiceClient.sharedInstance().call(accessToken, params: [:], delegate: strongSelf) //NOTE: The params here are not necessary as the phone numbers for now are hard coded on the server
if (strongSelf.call == nil) {
strongSelf.status = .callEnded
completion(false, .phoneCallFailed)
return
} else {
strongSelf.status = .callConnecting
self?.showActiveCallUI(withParameters: params)
completion(true, nil)
}
}
})
}
}
// MARK: TVOCallDelegate
func callDidConnect(_ call: TVOCall) {
NSLog("callDidConnect:")
self.call = call
status = .inCall
routeAudioToSpeaker()
}
func callDidDisconnect(_ call: TVOCall) {
NSLog("callDidDisconnect:")
playDisconnectSound()
self.call = nil
status = .callEnded
hideActiveCallUI()
}
func call(_ call: TVOCall, didFailWithError error: Error) {
NSLog("call:didFailWithError: \(error)");
self.call = nil
status = .callEnded
hideActiveCallUI()
}
}
注意：我也在您使用Twilio支持创建的票证中做出了回应 请检查您的帐户调试器，查看您收到的所有错误通知。下面是一个例子： 尝试从中检索内容 返回HTTP 状态代码500 Python web服务器返回了一条错误消息，其中包括： TypeError:create（）获取了意外的关键字参数 'status\u events'//Werkzeug调试器
这看起来像是Python outgoing（）函数中的代码错误。最值得注意的是，您正试图使用RESTAPI创建一个新调用，而实际上您应该返回TwiML。您应该返回包含拨号动词的TwiML，以创建传出呼叫分支。Twilio developer evangelist在此 您的Swift代码表示您的电话号码现在已在服务器上硬编码。正如Robert所说的那样，问题在于当您从Twilio获得对
/outbound/outbound@app.route('/outgoing', methods=['GET', 'POST'])
def outgoing():
from_number = [HARD_CODED_PHONE_NUMBER_FOR_CALLER]
to_number = [HARD_CODED_PHONE_NUMBER_FOR_RECIPIENT]
resp = twilio.twiml.Response()
with resp.dial(callerId=from_number) as r:
r.number(to_number)
return str(resp)
如果有帮助，请告诉我。您的TwiML应用程序语音URL指向什么？上面的
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