Python将数组打印成两个结果

我打印不出第二行

我试着用除以2，然后用2作为循环来打印它

A=[1,2,3,4,5,6,7,8]
w=len(A)
T=w/2
for i in range(T):
  for ii in range(T):
    print A[ii]


A=[1,2,3,4,5,6,7,8]

我想使用以下方式打印

[1,2,3,4]

和

[5,6,7,8]

：

输出：

[1, 2, 3, 4]
[5, 6, 7, 8]

[1, 2, 3, 4]
[5, 6, 7, 8]

编辑：

[1, 2, 3, 4]
[5, 6, 7, 8]

[1, 2, 3, 4]
[5, 6, 7, 8]

为了理解

A=[1,2,3,4,5,6,7,8]
w = len(A)

first_part = []
sec_part = []
count = 0                  # counter var to check for the first/sec half of list
for i in range((w)):
     if count < w//2:
          count += 1
          first_part.append(A[i])
     else:
      sec_part.append(A[i])

print(first_part)
print(sec_part)

使用列表切片：

A = [1,2,3,4,5,6,7,8]
print A[:len(A)/2]
print A[len(A)/2:]

产出将是：

[1,2,3,4]
[5,6,7,8]