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Python 如何将opencv的人脸检测边界框坐标转换为dlib的人脸检测边界框坐标?_Python_Opencv_Dlib_Coordinate Transformation - Fatal编程技术网

Python 如何将opencv的人脸检测边界框坐标转换为dlib的人脸检测边界框坐标?

Python 如何将opencv的人脸检测边界框坐标转换为dlib的人脸检测边界框坐标?,python,opencv,dlib,coordinate-transformation,Python,Opencv,Dlib,Coordinate Transformation,我使用opencv的预训练dnn模型和dlib的hog模型运行了一个实时流人脸检测代码。我从几个摄像头中得到检测结果,代码打印出opencv和dlib的边界框坐标。我期待同样的结果,但我有非常不同的结果。有没有办法将opencv坐标转换为dlib坐标 我试图找到一个数学线性模型来把它们联系起来,但没有成功 import numpy as np import argparse import imutils import pickle import time import cv2 import os

我使用opencv的预训练dnn模型和dlib的hog模型运行了一个实时流人脸检测代码。我从几个摄像头中得到检测结果,代码打印出opencv和dlib的边界框坐标。我期待同样的结果,但我有非常不同的结果。有没有办法将opencv坐标转换为dlib坐标

我试图找到一个数学线性模型来把它们联系起来,但没有成功

import numpy as np
import argparse
import imutils
import pickle
import time
import cv2
import os
import align
import dlib
import time
import datetime

face_detector = dlib.get_frontal_face_detector()
predictor_model = "shape_predictor_68_face_landmarks.dat"
face_aligner = align.AlignDlib(predictor_model)

ap = argparse.ArgumentParser()
ap.add_argument("-d", "--detector", required=True,
    help="path to OpenCV's deep learning face detector")
ap.add_argument("-m", "--embedding-model", required=True,
    help="path to OpenCV's deep learning face embedding model")
ap.add_argument("-r", "--recognizer", required=True,
    help="path to model trained to recognize faces")
ap.add_argument("-l", "--le", required=True,
    help="path to label encoder")
ap.add_argument("-c", "--confidence", type=float, default=0.8,
    help="minimum probability to filter weak detections")
args = vars(ap.parse_args())

print("[INFO] loading face detector...")
protoPath = os.path.sep.join([args["detector"], "deploy.prototxt"])
modelPath = os.path.sep.join([args["detector"],
    "res10_300x300_ssd_iter_140000.caffemodel"])
detector = cv2.dnn.readNetFromCaffe(protoPath, modelPath)
print("[INFO] starting video stream...")
vs = cv2.VideoCapture(0)
time.sleep(2.0)

while True:
    ret, frame = vs.read()
    frame = imutils.resize(frame, width=600)
    (h, w) = frame.shape[:2]
    imageBlob = cv2.dnn.blobFromImage(
        cv2.resize(frame, (300, 300)), 1.0, (300, 300),
        (104.0, 177.0, 123.0), swapRB=False, crop=False)
    detector.setInput(imageBlob)
    detections = detector.forward()
    for i in range(0, detections.shape[2]):
        confidence = detections[0, 0, i, 2]
        if confidence > args["confidence"]:
            box = detections[0, 0, i, 3:7] * np.array([w, h, w, h])
            (startX, startY, endX, endY) = box.astype("int")
            face = frame[startY:endY, startX:endX]
            (fH, fW) = face.shape[:2]
            if fW < 20 or fH < 20:
                continue
            rgb = cv2.cvtColor(face, cv2.COLOR_BGR2RGB)
            detected_faces_dlib = face_detector(rgb, 1)
            detected_faces = dlib.rectangle(left=startX, top=startY, right=endX, bottom=endY)
            print(detected_faces)
            print(detected_faces_dlib)

我刚刚花了很多时间处理这个问题,如果您的目标是检测dnn检测器检测到的人脸上的人脸标志,那么最好的办法是使用dnn检测器中的矩形重新训练shape_predictor_68_face_landmarks.dat

作为指导,我编写了一个python脚本,它遍历ibug300训练集,重新检测人脸的边界框,重写训练集的xml文件,然后运行train_shape_predictor脚本以获得一个新的.dat文件

与尝试重塑dnn矩形以近似hog box相比,结果非常好


在进行再培训之前,有一个提示:dnn人脸检测返回矩形,其宽度和高度变化很大。这对形状预测训练不起作用。最好使用边长为~1.35*dnn矩形宽度的正方形。这似乎是一个神奇的数字,但这是dnn人脸检测矩形的平均高宽比。

因此,如果我想使用opencv dnn人脸识别和dlib形状预测器,而不需要重新训练,我可以将每个dnn矩形变成正方形,然后将其传递给形状预测器吗?这是可行的吗?或者你能分享你训练过的.dat文件吗?对于其他发现这个问题的人,我在这里找到了很多代码,它们以不同的方式修改dnn矩形,以获得更好的地标:y1,x2=inty1*1.15,intx2*1.05
# take a bounding predicted by opencv and convert it
# to the dlib (top, right, bottom, left) 
def bb_to_rect(bb):
    top=bb[1]
    left=bb[0]
    right=bb[0]+bb[2]
    bottom=bb[1]+bb[3]
    return np.array([top, right, bottom, left]) 


# take a bounding predicted by dlib and convert it
# to the format (x, y, w, h) as we would normally do
# with OpenCV
def rect_to_bb(rect):

    x = rect.left()
    y = rect.top()
    w = rect.right() - x
    h = rect.bottom() - y

    # return a tuple of (x, y, w, h)
    return (x, y, w, h)
# take a bounding predicted by opencv and convert it
# to the dlib (top, right, bottom, left) 
def bb_to_rect(bb):
    top=bb[1]
    left=bb[0]
    right=bb[0]+bb[2]
    bottom=bb[1]+bb[3]
    return np.array([top, right, bottom, left]) 


# take a bounding predicted by dlib and convert it
# to the format (x, y, w, h) as we would normally do
# with OpenCV
def rect_to_bb(rect):

    x = rect.left()
    y = rect.top()
    w = rect.right() - x
    h = rect.bottom() - y

    # return a tuple of (x, y, w, h)
    return (x, y, w, h)