python中的出列函数

我正在使用线程。一个线程作为生产者线程，另一个线程作为消费者线程。线程从同一队列（q1）排队和出列。生产者功能似乎运行良好。但是，使用者线程（出列函数）给了我一个错误。下面是我的代码

def PacketProducer(Threadnum, numTicks, onProb, offProb, q):
   l=0
   onState = True
   packetId = 0
   for i in range(numTicks):
      x = generator(onProb, offProb, 'OnOff', onState)
      if(x==True):
            onState = True
            pkt = packet
            pkt.srcID = Threadnum
            pkt.pktId = packetId
            q.put(pkt)
            print(pkt.pktId, ' ', pkt.srcID)
            l = l+1
            packetId = packetId + 1
        else:
            onState = False
        time.sleep(1)
    #print(x)
    print(l/numTicks, ' threadNum', Threadnum)
    return

def PacketConsumer(q):  #dequeues and enqueues and returns the packet
    while True:
        if not q.empty():
            pkt = q.get()
            print('dequeuing Packet', ' ', pkt.pktId, pkt.srcID)
            time.sleep(1)
    return
if __name__ == '__main__':
    numTicks = 40
    q1 = Queue()
    pkt = packet
    x = threading.Thread(target=PacketProducer, args=(1, numTicks, 0.7, 0.7, q1))
    #y = threading.Thread(target=PacketProducer, args=(2, numTicks, 0.6, 0.4, q1))
    t = threading.Thread(target=PacketConsumer, args=(q1))
    t.start()
    x.start()
    #y.start()
    x.join()
#    y.join()
    t.join()

它给了我以下错误：

Exception in thread Thread-2:
Traceback (most recent call last):
  File "C:\Users\Syed\AppData\Local\Programs\Python\Python37-32\lib\threading.py", line 917, in _bootstrap_inner
    self.run()
  File "C:\Users\Syed\AppData\Local\Programs\Python\Python37-32\lib\threading.py", line 865, in run
    self._target(*self._args, **self._kwargs)
TypeError: PacketConsumer() argument after * must be an iterable, not Queue

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单个项元组中必须有一个

，

，以区分它本身，否则它只是分组括号

更改此行：

t = threading.Thread(target=PacketConsumer, args=(q1,))

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还要感谢@Marat，他和我同时提交了相同的解决方案（3秒后）。太棒了，请投票并勾选答案以结束讨论