当代码通过IDE和命令提示符运行时，Python线程行为不同

我在自动化一个我找到解决方案的网页时遇到了一个问题。 在我的回答中，第二个代码片段是

#Assume that at this point you are on the page where you need to click on a Web Element to      trigger native OS window/dialog box

def _action_on_trigger_element(_element):
    _element.click()

trigger_element = driver.find_element_by_id('ID of the Web Element which triggers the window')
th = threading.Thread(target = _action_on_trigger_element, args = [trigger_element])  #Thread is    created here to call private func to click on Save button
th.start()                          #Thread starts execution here
time.sleep(1)                       #Simple Thread Synchronization handle this case.          

#Call WindowFinder Class
win = WindowFinder()
win.find_window_wildcard(".*Save As.*") 
win.set_foreground()
path = "D:\\File.txt"            #Path of the file you want to Save 
ent = "{ENTER}"                  #Enter key stroke.
SendKeys.SendKeys(path)          #Use SendKeys to send path string to Save As dialog
SendKeys.SendKeys(ent)           #Use SendKeys to send ENTER key stroke to Save As dialog

#At this point the native OS window is interacted with and closed after passing a key stroke ENTER.
# Go forward with what ever your Automation code is doing after this point

当我从IDE

Aptana Studio3

运行代码时，代码运行良好，我的线程调用私有函数

\u action\u on\u trigger\u元素（\u元素）

但是当我通过调用

Python

脚本的命令行运行相同的代码时，线程不会调用作为其目标的函数

我检查过线还活着。对此和解决方法的任何解释都将不胜感激

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谢谢

这两个场景可能使用不同的环境吗？@Hyperboreus不一样唯一的区别是它们的触发方式。你说的“触发”是什么意思？@Hyperboreus我的意思是唯一的区别是脚本的执行方式。一个是在IDE内部，在这种情况下，它工作正常，只需一次通过命令行，线程从不调用私有函数。