Python 在turtle graphics中的同一位置反复擦除和重写文本和卡号？

注意力集中游戏要求用户在将一张牌与匹配的牌正确匹配之前能够将其翻转多次。这不是一直有效吗？它在第一次翻牌时就起作用了，但如果这张牌被跳过一圈，之后就会出现未定义的行为

import turtle
from turtle import *
import tkinter.font
from tkinter import *
import time

t = turtle.Turtle()
screen = Screen()
screen.setup(width=800, height=800, startx=10, starty=10)
eraseble = []

''' this function allows the square to be erased and rewriten '''
def erasableWrite(tortoise, name, font, align, reuse=None):
    eraser = turtle.Turtle() if reuse is None else reuse
    eraser.hideturtle()
    eraser.up()
    eraser.setposition(tortoise.position())
    eraser.write(name, font=font, align=align)
    print('eraser = {} name = {}.'.format(eraser, name))
    return eraser

startX = -280
startY = -295
textValue = [('1', 'a'), ('2', 'b'), ('3', 'c')]
t.hideturtle()
turtle.speed(0)
t.penup()
counter = 0
count = 0
for n in range(3):
    t.goto(startX, startY)
    t.pendown()
    eraseble.append(erasableWrite(t, textValue[n][0], font=("New Times Roman", 18, "normal"), align="center"))
    print('count = {}, eraseble[counter] = {} counter = {} n = {} textvalue = {}.  '.format(count, eraseble[counter], counter, n, textValue[n][0]))
    time.sleep(2)
    count += 1
    eraseble[counter].clear()
    eraseble.append(erasableWrite(t, textValue[n][1], font=("New Times Roman", 18, "normal"), align="center"))
    time.sleep(2)
    eraseble[counter + 1].clear()
    print('eraseble[counter] = {} counter = {} n = {} textvalue = {}.  '.format(eraseble[counter], counter, n, textValue[n][1]))
    eraseble[counter -1] = (erasableWrite(t, textValue[n][0], font=("New Times Roman", 18, "normal"), align="center"))
    count +=1
    startX +=40   
    startY += 20
    t.penup()
    counter +=2

    
` replace 1 with a `
startX = -280
startY = -295
t.goto(startX, startY)
print('count = {}, eraseble[0] = {}'.format(count, eraseble[0]))
count +=1
eraseble[0].clear()
textVal = textValue[0][0]
eraseble[0] = (erasableWrite(t, textVal, font=("New Times Roman", 18, "normal"), align="center"))
print('count = {}, eraseble[0] = {}'.format(count, eraseble[0]))
count +=1
eraseble[0].clear()
textVal = textValue[0][1]
eraseble[1] = (erasableWrite(t, textVal, font=("New Times Roman", 18, "normal"), align="center"))
time.sleep(2)

print('\n\neraseble = {}   !...!'.format(eraseble)) 

---

您似乎混淆了返回值和

重用
参数到
可擦除写入
的工作方式。我在下面重写了您的示例代码（稍微夸大了字体和距离）：

它显示三张“卡”及其值，然后返回并再次显示第一张卡的值，然后再将其隐藏起来。
您能把问题弄清楚吗？你到底在问什么？做得好#你解决了我的问题。使用你的代码，我可以完美地来回切换10次。哇！谢谢,谢谢,谢谢!！
from turtle import Screen, Turtle
import time

FONT = ("New Times Roman", 24, "bold")

def erasableWrite(tortoise, name, font, align, reuse=None):
    eraser = Turtle() if reuse is None else reuse
    eraser.hideturtle()
    eraser.up()
    eraser.setposition(tortoise.position())
    eraser.write(name, font=font, align=align)

    return eraser

screen = Screen()
screen.setup(width=800, height=800, startx=10, starty=10)

turtle = Turtle()
turtle.hideturtle()
turtle.penup()

erasable = []

startX = -280
startY = -295
textValue = [('1', 'a'), ('2', 'b'), ('3', 'c')]

for n in range(3):
    turtle.goto(startX, startY)

    erasable.append(erasableWrite(turtle, textValue[n][0], font=FONT, align="center"))
    time.sleep(2)
    erasable[n].clear()

    erasableWrite(turtle, textValue[n][1], font=FONT, align="center", reuse=erasable[n])
    time.sleep(2)
    erasable[n].clear()

    erasableWrite(turtle, textValue[n][0], font=FONT, align="center", reuse=erasable[n])

    startX += 80
    startY += 40

time.sleep(2)

startX = -280
startY = -295
turtle.goto(startX, startY)

erasable[0].clear()
textVal = textValue[0][1]
erasableWrite(turtle, textVal, font=FONT, align="center", reuse=erasable[0])
time.sleep(2)

erasable[0].clear()
textVal = textValue[0][0]
erasableWrite(turtle, textVal, font=FONT, align="center", reuse=erasable[0])
time.sleep(2)

screen.mainloop()