两个numpy数组上的Python zip
下面是一个工作示例，您可以复制所有变量并运行两个numpy数组上的Python zip,python,numpy,for-loop,indices,Python,Numpy,For Loop,Indices,下面是一个工作示例，您可以复制所有变量并运行for循环以检查 我有两个列表，一个是长度=13，另一个是长度=7 varying_DA = [70,78,86,90,94,98,100,102,106,110,114,122,130] test_array = [1,2,3,4,5,6,7,8,9,10,11,12,13] #DUMMY array varying_Hinv = [60,76,92,100,108,124,140] 我想循环浏览上述两个列表，即使用两个for循环，如： for v
forvarying_DA = [70,78,86,90,94,98,100,102,106,110,114,122,130]
test_array = [1,2,3,4,5,6,7,8,9,10,11,12,13] #DUMMY array
varying_Hinv = [60,76,92,100,108,124,140]
forfor vary_DA,test in zip(varying_DA,test_array):
for vary_Hinv,min_a,max_a in zip(varying_Hinv,min_aH,max_aH):
for70vary_DAvary_Hinvvary\u DA的78
，依此类推，直到vary\u DA的130
结束
对于每个vary\u DA
和vary\u Hinv
值，我有min\u aH
和max\u aH
的特定值
min_aH = np.array([[24,30,30,30,30,30,30],[36,42,42,47,47,47,47],
[36,42,42,42,42,42,42],[36,42,42,42,42,42,42],
[42,47,47,47,53,47,53],[42,53,47,47,53,53,53],
[47,47,47,47,47,53,47],[47,47,47,47,47,59,59],
[53,53,59,59,59,59,64],[47,65,59,59,47,47,64],
[53,47,41,47,53,47,47],[36,41,41,41,53,47,47],
[36,36,41,41,53,47,47]])
# As you can see it is a 13x7 matrix, 7 for the 7 different vary_Hinv
# values and 13 for the 13 different vary_DA values
max_aH = np.array([[54,60,60,60,60,60,60],[60,66,66,66,66,66,66],
[66,66,72,72,72,72,72],[66,72,72,72,78,78,78],
[72,78,78,78,84,84,84],[78,84,84,89,89,84,84],
[78,84,78,89,84,84,78],[84,84,78,84,84,89,89],
[84,84,84,89,89,89,89],[84,89,84,89,101,101,101],
[89,89,95,101,95,101,101],[96,96,95,107,95,101,101],
[96,101,95,107,107,101,101]])
即当vary_DA=70
和vary_Hinv=60
时，min_aH=24
和max_aH=54
。
当vary_DA=70
和vary_Hinv=76
时，min_aH=30
和max_aH=60
依此类推。
现在，我想将这些特定值min\u aH
和max\u aH
用于循环的，但从下面的工作示例中可以看出，它失败了
ii = 0
for vary_DA,test in zip(varying_DA,test_array):
jj = 0
for vary_Hinv,min_a,max_a in zip(varying_Hinv,min_aH,max_aH):
print vary_DA,vary_Hinv,ii,jj,min_aH[ii][jj],max_aH[ii][jj]
jj = jj + 1
ii = ii + 1
索引器错误：标量变量的索引无效。
底线：
当我能清楚地做到以下几点时：
In [12]: min_aH[0]
Out[12]: array([24, 30, 30, 30, 30, 30, 30])
In [13]: min_aH[0][0]
Out[13]: 24
为什么它在for
循环中失败？我如何让它工作
编辑：
我在上面的工作示例中犯了一个错误。在第二个for
循环中，打印应该是：
print vary_DA,vary_Hinv,ii,jj,min_a[ii][jj],max_a[ii][jj]
我以前有min\u-aH
和max\u-aH
而不是min\u-a
和max\u-a
。有没有人能告诉我上述方法是否有效 这在Python 3.6上适用：
varying_DA = [70,78,86,90,94,98,100,102,106,110,114,122,130]
test_array = [1,2,3,4,5,6,7,8,9,10,11,12,13] #DUMMY array
varying_Hinv = [60,76,92,100,108,124,140]
min_aH = np.array([[24,30,30,30,30,30,30],[36,42,42,47,47,47,47],
[36,42,42,42,42,42,42],[36,42,42,42,42,42,42],
[42,47,47,47,53,47,53],[42,53,47,47,53,53,53],
[47,47,47,47,47,53,47],[47,47,47,47,47,59,59],
[53,53,59,59,59,59,64],[47,65,59,59,47,47,64],
[53,47,41,47,53,47,47],[36,41,41,41,53,47,47],
[36,36,41,41,53,47,47]])
max_aH = np.array([[54,60,60,60,60,60,60],[60,66,66,66,66,66,66],
[66,66,72,72,72,72,72],[66,72,72,72,78,78,78],
[72,78,78,78,84,84,84],[78,84,84,89,89,84,84],
[78,84,78,89,84,84,78],[84,84,78,84,84,89,89],
[84,84,84,89,89,89,89],[84,89,84,89,101,101,101],
[89,89,95,101,95,101,101],[96,96,95,107,95,101,101],
[96,101,95,107,107,101,101]])
ii = 0
for vary_DA,test in zip(varying_DA,test_array):
jj = 0
for vary_Hinv,min_a,max_a in zip(varying_Hinv,min_aH,max_aH):
print(vary_DA,vary_Hinv,ii,jj,min_aH[ii][jj],max_aH[ii][jj])
jj = jj + 1
ii = ii + 1
下面是一些注释，首先，您的示例使用python 3运行时没有错误，输出为：
70 60 0 0 24 54
70 76 0 1 30 60
70 92 0 2 30 60
...
78 60 0 0 24 54
78 76 0 1 30 60
78 92 0 2 30 60
78 100 0 3 30 60
...
我不相信这是你想要的，因为最后四行的最后两个数字的值应该与前四行不同。我认为您希望显示的最后四行是：
78 60 1 0 36 60
78 76 1 1 42 66
78 92 1 2 42 66
78 100 1 3 47 66
根据你的描述。这是因为
ii=ii+1
在初始循环之外，因此ii始终不会更改值。工作版本（同样在python 3.6中）是：
ii = 0
for vary_DA,test in zip(varying_DA,test_array):
jj = 0
for vary_Hinv,min_a,max_a in zip(varying_Hinv,min_aH,max_aH):
print (vary_DA,vary_Hinv,ii,jj,min_aH[ii][jj],max_aH[ii][jj])
jj = jj + 1
ii = ii + 1
ii = 0
for vary_DA,test,min_a,max_a in zip(varying_DA,test_array,min_aH,max_aH):
jj = 0
for vary_Hinv,mn,mx in zip(varying_Hinv,min_a,max_a):
print (vary_DA,vary_Hinv,ii,jj,min_aH[ii][jj],max_aH[ii][jj],mn,mx)
jj = jj + 1
ii = ii + 1
尽管这根本没有利用压缩值，如果它尝试压缩，则无法实现所需的输出。你可以在这里看到，如果我打印出压缩的值，你只会得到每个列表中的最小值和最大值，但我相信你想要单独的值
ii = 0
for vary_DA,test in zip(varying_DA,test_array):
jj = 0
for vary_Hinv,min_a,max_a in zip(varying_Hinv,min_aH,max_aH):
print (vary_DA,vary_Hinv,ii,jj,min_aH[ii][jj],max_aH[ii][jj],min_a,max_a)
jj = jj + 1
ii = ii + 1
结果：
70 60 0 0 24 54 [24 30 30 30 30 30 30] [54 60 60 60 60 60 60]
70 76 0 1 30 60 [36 42 42 47 47 47 47] [60 66 66 66 66 66 66]
70 92 0 2 30 60 [36 42 42 42 42 42 42] [66 66 72 72 72 72 72]
...
78 60 1 0 36 60 [24 30 30 30 30 30 30] [54 60 60 60 60 60 60]
78 76 1 1 42 66 [36 42 42 47 47 47 47] [60 66 66 66 66 66 66]
78 92 1 2 42 66 [36 42 42 42 42 42 42] [66 66 72 72 72 72 72]
...
最后，正确使用zip来获得所需的值，从而使迭代器ii和jj变得不必要：
ii = 0
for vary_DA,test in zip(varying_DA,test_array):
jj = 0
for vary_Hinv,min_a,max_a in zip(varying_Hinv,min_aH,max_aH):
print (vary_DA,vary_Hinv,ii,jj,min_aH[ii][jj],max_aH[ii][jj])
jj = jj + 1
ii = ii + 1
ii = 0
for vary_DA,test,min_a,max_a in zip(varying_DA,test_array,min_aH,max_aH):
jj = 0
for vary_Hinv,mn,mx in zip(varying_Hinv,min_a,max_a):
print (vary_DA,vary_Hinv,ii,jj,min_aH[ii][jj],max_aH[ii][jj],mn,mx)
jj = jj + 1
ii = ii + 1
给予：
70 60 0 0 24 54 24 54
70 76 0 1 30 60 30 60
70 92 0 2 30 60 30 60
...
78 60 1 0 36 60 36 60
78 76 1 1 42 66 42 66
78 92 1 2 42 66 42 66
...
根据需要，最后删除迭代器，如下所示：
for vary_DA,test,min_a,max_a in zip(varying_DA,test_array,min_aH,max_aH):
for vary_Hinv,mn,mx in zip(varying_Hinv,min_a,max_a):
print (vary_DA,vary_Hinv,mn,mx)
这应该是我们想要的
我还能够使用Python2.7成功地运行您的示例代码和我的响应，因此我不确定基于这里的内容，您为什么会出现这种错误 我可以让你的代码运行没有错误。你的输入和你的问题完全一样吗？@jpp：它不是把索引器扔到print
行吗？i、 索引部分添加了我的完整代码作为答案（因为没有更好的方法）。如果复制粘贴，是否看到错误？如果您这样做，则可能是Python2.7v3.6的问题。