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Python 如何将三级词典转换为所需格式?_Python_Python 3.x_Pandas - Fatal编程技术网

Python 如何将三级词典转换为所需格式?

Python 如何将三级词典转换为所需格式?,python,python-3.x,pandas,Python,Python 3.x,Pandas,我有这样一本三级词典: data={'2016-11-28': {'area1': {'am': -0.007, 'pm': 0.008}, 'area2': {'am': 0.0, 'pm': 0.0}, 'area3': {'am': -0.01, 'pm': -0.001}},'2016-11-29':{'area1': {'am': -0.007, 'pm': 0.008}, 'area2': {'am': 0.0, 'pm': 0.0}, 'area3': {'am': -0.01,

我有这样一本三级词典:

data={'2016-11-28': {'area1': {'am': -0.007, 'pm': 0.008}, 'area2': {'am': 0.0, 'pm': 0.0}, 'area3': {'am': -0.01, 'pm': -0.001}},'2016-11-29':{'area1': {'am': -0.007, 'pm': 0.008}, 'area2': {'am': 0.0, 'pm': 0.0}, 'area3': {'am': -0.01, 'pm': -0.001}}}
我想将其转换为数据帧,并尝试:

tickers=data['2016-11-28'].keys()
iterables=[tickers,['am','pm']]
index=pd.MultiIndex.from_product(iterables, names=['ticker', 'time'])
frame=pd.DataFrame(data,index=index)
但是我有

                2016-11-28  2016-11-29
ticker time                        
area1  am           NaN         NaN
       pm           NaN         NaN
area3  am           NaN         NaN
       pm           NaN         NaN
area2  am           NaN         NaN
       pm           NaN         NaN

数据框中没有值,只有列名和索引名。我的代码怎么了?有人能帮忙吗?非常感谢

这里是我自己的解决方案:三重for循环强制字典符合分层索引的规则,即
{'col1':{('row1_level0','row1_level1'):value}

使用时会像这样

pd.DataFrame({'col1':{('rowidx0_level0', 'rowidx0_level1'):5}})

                         col1
rowidx0_level0 rowidx0_level1     5
这里是实现

d = {}
for date, areas in data.items():
    d[date] = {}
    for area, times in areas.items():
        for time, value in times.items():
            d[date][(area, time)] = value 

pd.DataFrame(d)

          2016-11-28  2016-11-29
area1 am      -0.007      -0.007
      pm       0.008       0.008
area2 am       0.000       0.000
      pm       0.000       0.000
area3 am      -0.010      -0.010
      pm      -0.001      -0.001
这就是实际字典
d
的样子:

{'2016-11-28': {('area1', 'am'): -0.007,
  ('area1', 'pm'): 0.008,
  ('area2', 'am'): 0.0,
  ('area2', 'pm'): 0.0,
  ('area3', 'am'): -0.01,
  ('area3', 'pm'): -0.001},
 '2016-11-29': {('area1', 'am'): -0.007,
  ('area1', 'pm'): 0.008,
  ('area2', 'am'): 0.0,
  ('area2', 'pm'): 0.0,
  ('area3', 'am'): -0.01,
  ('area3', 'pm'): -0.001}}
采用链接至@acushner的答案

dates = []
frames = []

for date, d in data.items():
    dates.append(date)
    frames.append(pd.DataFrame.from_dict(d, orient='index').stack())

pd.concat(frames, keys=dates, axis=1)

          2016-11-28  2016-11-29
area1 pm       0.008       0.008
      am      -0.007      -0.007
area2 pm       0.000       0.000
      am       0.000       0.000
area3 pm      -0.001      -0.001
      am      -0.010      -0.010