Python Flask-使用sendgrid API上载Wtforms文件
我正在制作一个相对简单的表单,它有一个文件输入字段。我显然希望将上传的文件附加到通过Sendgrid python api发送的电子邮件中。表单此时已成功发送,但我没有收到任何文件上载,这是我迄今为止制作的: HTMLPython Flask-使用sendgrid API上载Wtforms文件,python,flask,sendgrid,Python,Flask,Sendgrid,我正在制作一个相对简单的表单,它有一个文件输入字段。我显然希望将上传的文件附加到通过Sendgrid python api发送的电子邮件中。表单此时已成功发送,但我没有收到任何文件上载,这是我迄今为止制作的: HTML <form action="" method="post" name="property_info" class="clearfix" enctype="multipart/form-data"> ...really long form, but here is
<form action="" method="post" name="property_info" class="clearfix" enctype="multipart/form-data">
...really long form, but here is the file input field
<input type="file" id="upfile">
...more input fields..
</form>
excel\u email.py
app.config['UPLOAD_FOLDER'] = config.UPLOAD_FOLDER
app.config['ALLOWED_EXTENSIONS'] = config.ALLOWED_EXTENSIONS
#Check if the uploaded excel file has one of the three allowed file extensions
def allowed_file(filename):
return '.' in filename and \
filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS
@app.route('/', methods=['GET','POST'])
def index():
form = forms.GeneralProperty()
year = datetime.date.today().year
if form.validate_on_submit():
print 'form is valid'
#upload excel file if it's present
print request.files
if form.excel_file.data:
print 'there is a file uploaded'
file = request.files['file']
print 'file is ' + str(file)
if file and allowed_file(file.filename):
print 'file is allowed'
filename = secure_filename(file.filename)
print 'filename is ' + filename
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
#Send e-mail with attached excel file
print 'going into email function'
excel_email.send_mail(form, excel_file=filename)
#Otherwise, ignore the excel file
else:
excel_email.send_mail(form)
flash('Thanks for submitting the form ' + form.person_name.data.split(' ')[0] + '! We will be in contact with you shortly.', 'bg-success')
elif form.errors:
flash('There was an error submitting the form, please check that all required fields are filled in.', 'bg-danger')
return render_template('index.html', form=form, year=year)
#Setting up email send method
def send_mail(form, excel_file=None):
sg = sendgrid.SendGridClient('username', 'password')
print 'Starting mail process....'
message = sendgrid.Mail()
message.add_to(str(form.person_email.data))
message.set_from('example@heroku.com')
message.set_from_name(str(form.person_name.data))
message.set_subject('Property Form Submission')
message.set_html(...really long HTML email template with all form data...)
#If the excel file is attached, attach it to the e-mail
if excel_file:
message.add_attachment(excel_file)
status, msg = sg.send(message)
print status
print msg
在本地主机上运行时从控制台输出
form is valid
ImmutableMultiDict([])
Starting mail process....
200
{"message":"success"}
非常感谢您的建议:)您需要给输入一个名称。在您的视图中,您将获得
request.files['file']
,因此输入必须具有名称“file”
您需要给输入一个名称。在您的视图中,您将获得
request.files['file']
,因此输入必须具有名称“file”
您需要给输入一个名称。在您的视图中,您将获得
request.files['file']
,因此输入必须具有名称“file”
您需要给输入一个名称。在您的视图中,您将获得
request.files['file']
,因此输入必须具有名称“file”
<input type="file" name="file"/>
{{ form.file }}