Maya Python API图像平面数学
有人知道基于相机外光圈、焦距、过扫描和分辨率计算图像平面的数学吗 基本上,我只是尝试创建一个平面,它基于表示图像平面的当前视口 谢谢你的帮助。Maya Python API图像平面数学,python,api,math,maya,plane,Python,Api,Math,Maya,Plane,有人知道基于相机外光圈、焦距、过扫描和分辨率计算图像平面的数学吗 基本上,我只是尝试创建一个平面,它基于表示图像平面的当前视口 谢谢你的帮助。 花了很多时间才找到它 您几乎肯定会遇到一个令人恼火的问题,即Maya将摄影机后光圈存储为英寸,而焦距存储为毫米。因此: import math import maya.cmds as cmds import maya.OpenMaya as OpenMaya # maya uses INCHES for camera backs # but MILL
花了很多时间才找到它 您几乎肯定会遇到一个令人恼火的问题,即Maya将摄影机后光圈存储为英寸,而焦距存储为毫米。因此:
import math
import maya.cmds as cmds
import maya.OpenMaya as OpenMaya
# maya uses INCHES for camera backs
# but MILLIMETERS for focal lenghts. Hence the magic number 25.4
def get_vfov (camera):
'''
returns the vertical fov the supplied camera, in degrees.
'''
fl = cmds.getAttr(camera + ".focalLength")
vfa = cmds.getAttr(camera + ".vfa") * 25.4 # in mm
return math.degrees ( 2 * math.atan(vfa / (2 * fl)))
def get_hfov (camera):
'''
returns the horizontal fov the supplied camera, in degrees.
'''
fl = cmds.getAttr(camera + ".focalLength")
vfa = cmds.getAttr(camera + ".hfa") * 25.4 # in mm
return math.degrees ( 2 * math.atan(vfa / (2 * fl)))
def get_persp_matrix (FOV, aspect = 1, near = 1, far = 30):
'''
give a FOV amd aspect ratio, generate a perspective matrix
'''
matrix = [0.0] * 16
fov = math.radians(FOV)
yScale = 1.0 / math.tan(fov / 2)
xScale = yScale / aspect
matrix[0] = xScale
matrix[5] = yScale
matrix[10] = far / (near - far)
matrix[11] = -1.0
matrix[14] = (near * far) / (near - far)
mmatrix = OpenMaya.MMatrix()
OpenMaya.MScriptUtil.createMatrixFromList( matrix, mmatrix )
return mmatrix