Python 循环以创建动态变量
我有以下代码:Python 循环以创建动态变量,python,Python,我有以下代码: if opt1 is not None: user_a, db_a = opt1.split("/") db_a = country_assoc(int(db_a)) client_a = Client(None, user_a, db_a) data_client_a = client_a.get_user() if opt2 is not None: user_b, db_b
if opt1 is not None:
user_a, db_a = opt1.split("/")
db_a = country_assoc(int(db_a))
client_a = Client(None, user_a, db_a)
data_client_a = client_a.get_user()
if opt2 is not None:
user_b, db_b = opt2.split("/")
db_b = country_assoc(int(db_b))
client_b = Client(None, user_b, db_b)
data_client_b = client_b.get_user()
....
但是,我想用一个循环生成一个类似的结构
正确的方法是什么?我正在尝试这个
abcde = ['a', 'b', 'c', 'd', 'e']
for idx, val in enumerate(abcde):
if opt+idx is not None:
user_+val, db_+val = opt+idx.split("/")
db_+val = country_assoc(int(db_+val))
client_+val = Client(None, user_+val, db_+val)
data_client_+val = client_+val.get_user()
我不明白为什么人们觉得有必要尝试做这种事情。变量名不是数据。动态创建变量名从来都不是一个好的理由 只需将您的值放入字典或列表中
for idx, val in enumerate(abcde):
if opts[idx] is not None:
user, db = opts[idx].split("/")
users[val] = user
dbs[val] = country_assoc(int(db))
clients[val] = Client(None, user, db)
data_clients.append(clients[val].get_user())
我不明白为什么人们觉得有必要尝试做这种事情。变量名不是数据。动态创建变量名从来都不是一个好的理由 只需将您的值放入字典或列表中
for idx, val in enumerate(abcde):
if opts[idx] is not None:
user, db = opts[idx].split("/")
users[val] = user
dbs[val] = country_assoc(int(db))
clients[val] = Client(None, user, db)
data_clients.append(clients[val].get_user())