Python 用于查找重复项和更新顶点属性的Gremlin查询
我想查找重复记录并将属性Python 用于查找重复项和更新顶点属性的Gremlin查询,python,gremlin,amazon-neptune,gremlin-server,gremlinpython,Python,Gremlin,Amazon Neptune,Gremlin Server,Gremlinpython,我想查找重复记录并将属性isDuplicate更新为yes 我能够找到重复记录,但找不到更新属性的方法 g.V() \ .has("customerId") \ .group().by("customerId") \ .unfold() \ .toList() 上述查询还返回单个记录。我也想删除它们。这里有一种方法: gremlin> g = TinkerGraph.open().traversal() ==>graphtraversals
isDuplicate
更新为yes
我能够找到重复记录,但找不到更新属性的方法
g.V() \
.has("customerId") \
.group().by("customerId") \
.unfold() \
.toList()
上述查询还返回单个记录。我也想删除它们。这里有一种方法:
gremlin> g = TinkerGraph.open().traversal()
==>graphtraversalsource[tinkergraph[vertices:0 edges:0], standard]
gremlin> g.addV('person').property('customerId','alice').
......1> addV('person').property('customerId','alice').
......2> addV('person').property('customerId','bob').
......3> addV('person').property('customerId','alice').iterate()
gremlin> g.V().hasLabel('person').has('customerId').
......1> group().by('customerId').
......2> unfold().
......3> select(values).filter(count(local).is(gt(1))).unfold().
......4> property('isDuplicate','yes')
==>v[0]
==>v[2]
==>v[6]
gremlin> g.V().elementMap()
==>[id:0,label:person,customerId:alice,isDuplicate:yes]
==>[id:2,label:person,customerId:alice,isDuplicate:yes]
==>[id:4,label:person,customerId:bob]
==>[id:6,label:person,customerId:alice,isDuplicate:yes]
以下是一种方法:
gremlin> g = TinkerGraph.open().traversal()
==>graphtraversalsource[tinkergraph[vertices:0 edges:0], standard]
gremlin> g.addV('person').property('customerId','alice').
......1> addV('person').property('customerId','alice').
......2> addV('person').property('customerId','bob').
......3> addV('person').property('customerId','alice').iterate()
gremlin> g.V().hasLabel('person').has('customerId').
......1> group().by('customerId').
......2> unfold().
......3> select(values).filter(count(local).is(gt(1))).unfold().
......4> property('isDuplicate','yes')
==>v[0]
==>v[2]
==>v[6]
gremlin> g.V().elementMap()
==>[id:0,label:person,customerId:alice,isDuplicate:yes]
==>[id:2,label:person,customerId:alice,isDuplicate:yes]
==>[id:4,label:person,customerId:bob]
==>[id:6,label:person,customerId:alice,isDuplicate:yes]
这是有效的。谢谢,这很有效。非常感谢。