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Python 计算特定跨距数据帧中的累积和_Python_Pandas_Cumulative Sum - Fatal编程技术网

Python 计算特定跨距数据帧中的累积和

Python 计算特定跨距数据帧中的累积和,python,pandas,cumulative-sum,Python,Pandas,Cumulative Sum,我有福勒。数据帧: tot_pix Season caap_col lamma kite datetime 2000-01-01 1914.0 2000.0 1.0 1.95025 117.737362 2000-01-04 1914.0 2000.0 1.0 1.95025 117.674177 2000-01

我有福勒。数据帧:

            tot_pix  Season  caap_col    lamma     kite
datetime                                                  
2000-01-01   1914.0  2000.0       1.0  1.95025  117.737362
2000-01-04   1914.0  2000.0       1.0  1.95025  117.674177
2000-01-05   1914.0  2000.0       1.0  1.95025  117.995489
2001-01-04   1914.0  2001.0       1.0  1.95025  118.114809
2001-01-05   1914.0  2001.0       1.0  1.95025  118.160295
在上面的数据框中,我想计算
kite
列的累积和。但是,我希望累积总和不跨越
季节
值。例如,
kite
的累积和输出应如下所示:

          tot_pix Season caap_col lamma kite
datetime                    
1/1/2000    1914    2000    1   1.95025 117.737362
1/4/2000    1914    2000    1   1.95025 235.411539
1/5/2000    1914    2000    1   1.95025 235.669666
1/4/2001    1914    2001    1   1.95025 118.114809
1/5/2001    1914    2001    1   1.95025 236.275104
我可以使用
cumsum
命令计算累计总和,如何将其限制为
季节的特定跨度?

您需要+:

#if not sorted index with column Season
#df = df.sort_index(sort_remaining=True).sort_values('Season')

df['kite'] = df.groupby('Season')['kite'].cumsum()
print (df)
           tot_pix  Season  caap_col    lamma        kite
datetime                                                  
2000-01-01   1914.0  2000.0       1.0  1.95025  117.737362
2000-01-04   1914.0  2000.0       1.0  1.95025  235.411539
2000-01-05   1914.0  2000.0       1.0  1.95025  353.407028
2001-01-04   1914.0  2001.0       1.0  1.95025  118.114809
2001-01-05   1914.0  2001.0       1.0  1.95025  236.275104