python字母猜谜游戏
我第一次真正尝试了python程序——一个猜字母的游戏 大部分的工作我都做完了,但最后一点工作我还没做完 我想让游戏在用户和人工智能之间来回交替,直到世界完全展现出来。到目前为止,我很好。在这一点上,我想让玩家猜对最多的字母赢得一分。电脑主持人选择另一个单词,然后重新开始。第一个得五分的玩家赢得比赛 我有一个while循环,在用户/人工智能转换之间交替,但是一旦这个词完全公开,我就不能让它正确地中断?在这之后,比较userCorrectLetters的数量和AicCorrectLetters的数量应该很简单,然后用它来确定谁在这一轮中获胜 然后,我假设整个过程应该进入一个while循环,直到其中一个玩家达到5分才停止 我遇到的另一个问题是如何禁止用户重新猜测已经解决的角色位置python字母猜谜游戏,python,loops,Python,Loops,我第一次真正尝试了python程序——一个猜字母的游戏 大部分的工作我都做完了,但最后一点工作我还没做完 我想让游戏在用户和人工智能之间来回交替,直到世界完全展现出来。到目前为止,我很好。在这一点上,我想让玩家猜对最多的字母赢得一分。电脑主持人选择另一个单词,然后重新开始。第一个得五分的玩家赢得比赛 我有一个while循环,在用户/人工智能转换之间交替,但是一旦这个词完全公开,我就不能让它正确地中断?在这之后,比较userCorrectLetters的数量和AicCorrectLetters的数
import random
#set initial values
player1points= 0
ai= 0
userCorrectLetters= []
aiCorrectLetters=[]
wrongLetters=[]
wrongPlace= []
correctLetters = []
endGame = False
allLetters = set(list('abcdefghijklmnopqrstuvwxyz'))
alreadyGuessed = set()
userGuessPosition = 0
availLetters = allLetters.difference(alreadyGuessed)
#import wordlist, create mask
with open('wordlist.txt') as wordList:
secretWord = random.choice(wordList.readlines()).strip()
print (secretWord)
secretWordLength = len(secretWord)
def displayGame():
mask = '_' * len(secretWord)
for i in range (len(secretWord)):
if secretWord[i] in correctLetters:
mask = mask[:i] + secretWord[i] + mask [i+1:]
for letter in mask:
print (letter, end='')
print (' ')
print ('letters in word but not in correct location:', wrongPlace)
print ('letters not in word:', wrongLetters)
##asks the user for a guess, assigns input to variable
def getUserGuess(alreadyGuessed):
while True:
print ('enter your letter')
userGuess = input ()
userGuess= userGuess.lower()
if len(userGuess) != 1:
print ('please enter only one letter')
elif userGuess in alreadyGuessed:
print ('that letter has already been guessed. try again')
elif userGuess not in 'abcdefjhijklmnopqrstuvwxyz':
print ('only letters are acceptable guesses. try again.')
else:
return userGuess
def newGame():
print ('yay. that was great. do you want to play again? answer yes or no.')
return input().lower().startswith('y')
def userTurn(wrongLetters, wrongPlace, correctLetters):
print ('\n')
displayGame ()
print ('which character place would you like to guess. Enter number?')
userGuessPosition = input ()
if userGuessPosition not in ('123456789'):
print ('please enter a NUMBER')
userGuessPosition = input()
slice1 = int(userGuessPosition) - 1
##player types in letter
guess = getUserGuess(wrongLetters + correctLetters)
if guess== (secretWord[slice1:int(userGuessPosition)]):
print ('you got it right! ')
correctLetters.append(guess)
userCorrectLetters.append(guess)
displayGame()
elif guess in secretWord:
wrongPlace.append(guess)
print ('that letter is in the word, but not in that position')
displayGame()
else:
wrongLetters.append(guess)
print ('nope. that letter is not in the word')
displayGame()
def aiTurn(wrongLetters,wrongPlace, correctLetters):
print ('\n')
print ("it's the computers turn")
aiGuessPosition = random.randint(1, secretWordLength)
aiGuess=random.sample(availLetters, 1)
print ('the computer has guessed', aiGuess, "in position", + aiGuessPosition)
slice1 = aiGuessPosition - 1
if str(aiGuess) == (secretWord[slice1:userGuessPosition]):
correctLetters.append(aiGuess)
aiCorrectLetters.append(aiGuess)
print ('this letter is correct ')
return
elif str(aiGuess) in secretWord:
wrongPlace.append(aiGuess)
print ('that letter is in the word, but not in that position')
return
else:
wrongLetters.append(aiGuess)
print ('that letter is not in the word')
return
wordSolved = False
while wordSolved == False:
userTurn(wrongLetters, wrongPlace, correctLetters)
aiTurn(wrongLetters, wrongPlace, correctLetters)
if str(correctLetters) in secretWord:
break
问题在于:
if str(correctLetters) in secretWord:
您可能期望str(['a','b','c'])
返回'abc',但它没有。它返回“['a','b','c']”
。
应将该行替换为:
if "".join(correctLetters) in secretWord:
除此之外,您的代码还有一个问题:
假设正确的单词是foobar
。如果用户猜到前5个字母,但顺序相反,correctLetters
将是['a','b','o','o','f']
,行If'。在secretWord中连接(correctLetters):
将计算为False
因为'aboof'
不在'foobar'
中
您可以通过将secretWord:中的if''替换为以下内容来解决该问题:
if len(correctLetters) > 4:
基本上,只要用户猜出5个正确的字母,程序的执行就会结束。无需检查字母是否在secretWord
中,因为您已经在userTurn
功能中进行了检查。您正在比较列表correctLetters
的字符串表示形式与字符串secretWord
。例如:
>>> secretWord = 'ab'
>>> correctLetters = ['a','b']
>>> str(correctLetters)
"['a', 'b']"
>>> str(correctLetters) in secretWord
False
尝试将由正确字母组成的字符串与机密单词进行比较:
>>> ''.join(correctLetters) == secretWord
True
你把worldSolved设置为真了吗?只是尝试了一下,还是没有正确地断开。我想这是因为str(correctLetters)和secretWord之间的比较有问题?你在secretWord中的str(correctLetters)上想做什么