困在第36个练习中艰难地学习Python

这是我为练习36编写的代码。但是我无法运行

door_1

功能中的代码。如果我选择3作为选项，然后向左或向右选择任何存储在dir中的内容，那么无论我键入什么，输出都是“lion吃了你”

from sys import exit #importing module from lib

def Tadaa():
    print "This is a place where you will get a surprise"
    next = int(raw_input("Enter any number from 1-10 :"))
    if next <= 10:  
        if next % 2 == 0 :
            print "You will be buying me a shake :)."
        else :
            print "You will be getting a shake by me."
    else :
        print "Do it correctly."

def door_1():
    print "There are 3 doors . Choose any door from the the remaining three doors"
    print "Lets hope for the best "
    next = raw_input("Enter your option :")
    if next == "1":
        print "abc "
    elif next == "2": 
        print "abc"
    elif next == "3":
        print "You have entered 3rd door ."
        print "Here are 2 doors one on left and one on right."

        dir = raw_input("Choose which door do you wnat to enter :")

        if dir == "left" or "Left":
            print "Lion ate you . You are dead ."
        elif dir == "right" or "Right" :
            print "You will be getting a surprise"
            Tadaa()
        else :
            print "abc"
    else :
        print "abc"

def door_2():
    print "There are two doors A and B which will decide your fate"

    next = raw_input("Enter the door ")

    if next == "A" or "a":
        door_1()            
    elif next == "B" or "b":
        print "You are back from where you have started"
        start()
    else :
        print "I got no idea what that means."
        exit(0)

def start():
    print "You are in dark room"
    print "There is a door to your right and left ."
    print "Which one do you take"

    next = raw_input("> ")

    if next == "Right" or "right":
        door_2()
    elif next == "Left" or "left":
        door_1()
    else :
        print "abc"
start()

从系统导入退出#从库导入模块
def Tadaa（）：
打印“这是一个你会得到惊喜的地方”
next=int（原始输入（“输入1-10之间的任意数字”））
如果下一步问题在于你的陈述：

if dir=="left" or "Left":

你想要的是

if dir=="left" or dir=="Left":

实际上，刚才所做的
或“Left”
就是检查您刚刚创建的字符串是否存在。换句话说，它类似于：

x='Left'
if x:

X确实存在，所以如果X

为

True

---

这里的关键是始终在quantum中计算语句，当您将

和

与

或

语句结合使用时，请确保使用括号来明确表示<代码>如果语句\u-one或语句\u-two

但如果您看到start（）函数，您将看到我对下一个语句也做了同样的操作，但它确实运行。我现在还不确定，但我可以告诉你一个事实，那就是如果语句不正确，你是如何评估的：）按照上面演示的方法正确操作，看看这是否解决了你的问题。如果你知道下一个语句，一定要让我知道：）就像我说的，把它全部解决。例如，如果next=='Right'或next=='Right'，则应该使用

。我不知道为什么它现在似乎工作得很好，但我相信它的错误代码和它的工作只是侥幸。调试代码很好，调试函数代码有时很难。